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pentagon [3]
2 years ago
7

Harper knows he is 50 yards from school. The map on his phone shows that the school is 2/3 inch from his current location. How f

ar is Harper from home, if the map shows the distance as 3 inches?
Mathematics
2 answers:
lorasvet [3.4K]2 years ago
6 0

Actual distance of the Harper from the school = 50 yards.

According to map the distance from the school = 34 inch.

We could say 34 inches represents 50 yards.

So, 1 inches could be represented by 50/34 = 25/17 yards.

In order to find the actual length of 3 inches in yards, we need to multiply 1 inches value of yards by 3.

Therefore, 3 inches = 3* 25/17 = 75/17 = 4 7/17 yeards in decimals 4.412 yards approximately.

Therefore,  Harper from home is  4 7/17 yeards or 4.412 yards approximately if the map shows the distance as 3 inches.

Rashid [163]2 years ago
3 0

Answer:

Actual distance of the Harper from the school = 50 yards.

According to map the distance from the school = 34 inch.

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Please see the attachment

From the figure, it is evident that

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Thus, cos-1 (0.53) = 58 degrees

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5 0
3 years ago
PLEASE HELP!!!!!!!!!!
yan [13]

115 = l \times 2.5 \times 5.75

\huge \mathrm{Answer࿐}

given :

\longmapsto volume = 115 yd³

Dimensions are :

  • 2\frac{1}{2} yd

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We know,

\large \boxed{ \mathrm{volume = l \times b \times h}}

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  • l  \times  \dfrac{115}{8} = 115

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Therefore Length of the prism is 8 yards.

_____________________________

\mathrm{ \#TeeNForeveR}

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Equation 1)  4x + 2y = 8
Equation 2)  16x - y = 14

Multiply all of equation 2 by 2.

2)  2(16x - y = 14)

2)  32x - 2y = 28
1)  4x + 2y = 8

Add equations together.

36x = 36

Divide both sides by 36.

x = 1

Plug in 1 for x in the first equation.

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Subtract 4 from both sides.

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Divide both sides by 2.

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7 0
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