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Ganezh [65]
2 years ago
13

Consider the two-way table below. A 4-column table has 3 rows. The first column has entries A, B, total. The second column is la

beled C with entries 15, 9, 24. The third column is labeled D with entries 21, 25, 46. The fourth column is labeled Total with entries 36, 34, 70. Find P(B|C). P(B|C) = StartFraction 9 Over 34 EndFraction = 0. 26 P(B|C) = StartFraction 9 Over 24 EndFraction = 0. 38 P(B|C) = StartFraction 9 Over 70 EndFraction = 0. 13 P(B|C) = StartFraction 9 Over 58 EndFraction = 0. 16.
Mathematics
1 answer:
Nat2105 [25]2 years ago
4 0

The probability is the ratio of the favorable event to the total number of events. Then the P(B|C) is 0.38. Then the correct option is B.

<h3>What is probability?</h3>

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen.

According to the condition, the table will be

                      C                   D               Total

  A                 15                  21                 36

  B                  9                  25                34

Total              24                 46                70

The probability of the (BIC) will be

\rm P(B|C) = \dfrac{9}{24}\\\\\\P(B|C) = 0.375 \approx 0.38

The P(B|C) is 0.38. Then the correct option is B.

More about the probability link is given below.

brainly.com/question/795909

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What is the equation of the line and a slope intercept form that passes through 3, -1 and -1, 5
TEA [102]

ANswer:  y= -3/2x + 7/2

you welcome

7 0
2 years ago
Andy is collecting pocket change for a fundraiser. he begins with 102 coins in the cup, and their monetary value is $17.10. if h
Ira Lisetskai [31]

If Andy has 102 coins mixed with dimes and quarters and monetary value of $17.10 then he has 56 dimes and 42 quarters.

Given number of coins Andy has is 102 and montary value of all coins is $17.10.

We have to determine number of dimes and quarters.

1 dime=$0.10

1 quarter=$0.25

Suppose the number of dimes be x and number of quarters be y.

The equations are:

0.10x+0.25y=17.10------------1

x+y=102-------------2

from equation 2, y=102-x

Put the value of y=102-x in equation 1

0.10x+0.25(102-x)=17.10

0.10x+25.5-0.25x=17.10

-0.15x=17.10-25.5

-0.15x=-8.4

x=8.4/0.15

x=56

Put the value of x in y=102-x

y=102-56

y=46

Hence Andy has 56 number of dimes and 46 quarters.

Learn more about equation at brainly.com/question/2972832

#SPJ4

5 0
2 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
Solve for x: 0.75x-0.25=3.5
exis [7]

Answer:

x=5

Step-by-step explanation:

3.5=0.75x-0.25

add 0.25 to 3.5

3.75=0.75x

divide 3.75 by 0.75

x=5

4 0
3 years ago
Find the missing angle in the diagram.<br><br> Help asap (Ty!)
Mila [183]
94 ANSWER hope this helps
5 0
1 year ago
Read 2 more answers
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