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3 years ago

CAN SOMEBODY PLEASE HELP ME ON CHEMISTRY OF 8 th Grade on my exam

Chemistry

1 answer:

il63 [147K]3 years ago

7 0

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What is the density of an object that has a mass of 149. 8 g and displaces 12. 1 ml of water when placed in a graduated cylinder

kozerog [31]

Answer:

Explanation:

The density of a substance can be found by using the formula

$d = \frac{m}{v} \\$

m is the mass

v is the volume

From the question

m = 149.8 g

v = 12.1 mL

We have

$d = \frac{149.8}{12.1} = 12.380165... \\$

We have the final answer as

Hope this helps you

4 0

2 years ago

The minimum energy colliding particles must have in order to react is known as _____ energy. A. dynamic B. disorder C. activatio

PtichkaEL [24]

The answer is C activation

4 0

4 years ago

Read 2 more answers

Which substance loses electrons in a chemical reaction

Ierofanga [76]

Answer:

Explanation:

Reducing agent

Reducing agent is an element or compound that loses or donates an electron to another chemical species in a redox chemical reaction. Since the reducing agent is losing electrons,it is said to have been oxidized.

8 0

3 years ago

7) For the reaction 9A (g) + B (g)  5C(g) + 1/6 D (g), it takes 4 and a half minutes for the concentration of C to increase to

viva [34]

Answer: The correct option is, (C) 0.53

Explanation:

The given chemical reaction is:

$9A(g)+B(g)\rightarrow 5C(g)+\frac{1}{6}D(g)$

The rate of the reaction for disappearance of A and formation of C is given as:

$\text{Rate of disappearance of }A=-\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}$

Or,

$\text{Rate of formation of }C=+\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}$

where,

$\Delta C$ = change in concentration of C = 1.33 M

$\Delta t$ = change in time = 4.5 min

Putting values in above equation, we get:

$\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}=\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}$

$\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{\Delta [C]}{\Delta t}$

$\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{1.33M}{4.5min}$

$\frac{\Delta [A]}{\Delta t}=0.53M/min$

Thus, the decrease in A during this time interval is, 0.53

5 0

3 years ago

HOW IS A COMPOUND DIFFERENT FROM A MIXTURE?

valentinak56 [21]

D.It can not be separated by a physical change.

7 0

3 years ago