Answer:
E = 3.6×10⁻¹⁹ J
Explanation:
Given data:
Wavelength = 550 nm (550 ×10⁻⁹ nm)
Energy of wave = ?
Solution:
Formula:
E = h c/λ
c = 3×10⁸ m/s
h = 6.63×10⁻³⁴ Js
Now we will put the values in formula.
E = 6.63×10⁻³⁴ Js × 3×10⁸ m/s /550 ×10⁻⁹ nm
E = 19.89×10⁻²⁶ J.m /550 ×10⁻⁹ nm
E = 0.036×10⁻¹⁷ J
E = 3.6×10⁻¹⁹ J
Density is a property of the substances that is obtained by dividing its mass by the volume. For a rectangular solid, the volume may be solved by the following equation,
V = L x W x H
Substituting the given values for the dimension,
V = (2.30 cm) x (4.01 cm) x (1.82 cm) = 16.78786 cm³
Calculating for the density,
Density = mass / volume
Density = 25.71 cm / <span>16.78786 cm³ = 1.53 grams per cm</span>³
Thus, the density of the given solid is approximately 1.53 grams per cm³.
The value for ΔG = 18 kJ/mol
<h3>Further explanation</h3>
Given
ΔH = 27 kJ/mol and ΔS = 0.09 kJ/mol.K
T = 100 K
Required
the value for ΔG
Solution
The spontaneous process of a reaction is based on 2 factors :
- enthalpy change ΔH decreases and
- entropy change ΔS increases
ΔG=ΔH-T.ΔS
In a balanced chemical equation, we have two numbers that indicate two different factors. The definitions of these numbers are as follows:
1- Molar ratio: This ratio represents the ratio between the number of moles of any two substances in the balanced equation
2- The coefficients in the balanced chemical equation: These numbers represent the numbers of particles of each of the substances taking place in this chemical equation.
Answer:
The mass of
4.6
×
10
24
atoms of silver is approximately 820 g.
Explanation:
In order to determine the mass of a given number of atoms of an element, identify the equalities between moles of the element and atoms of the element, and between moles of the element and its molar mass.
1
mole atoms Ag=6.022xx10
23
atoms Ag
Molar mass of Ag =#"107.87 g/mol"#
Multiply the given atoms of silver by
1
mol Ag
6.022
×
23
atoms Ag
. Then multiply times the molar mass of silver.
4.6
×
10
24
atoms Ag
×
1
mol Ag
6.022
×
10
23
atoms Ag
×
107.87
g Ag
1
mol Ag
=
820 g Ag
