In this case, the parental are lengthwise stripes (genotype ls/ls) and plaid stripes (genotype Ps/Ps), the F1 is plaid (100%) and F2 is plaid (75%) and lengthwise (25%). It is a Mendelian inheritance pattern.
<h3>Mendelian inheritance and complete dominance</h3>
Complete dominance occurs when the dominant allele (in this case, the plaid stripe trait) completely masks the recessive allele (lengthwise stripes) in heterozygous individuals.
The cross between tigers having lengthwise stripes (genotype ls/ls) and plaid stripes (genotype Ps/Ps) will produce an F1 100% having the plaid stripes (genotype Ps/ls) trait because this trait is dominant.
In the F2 obtained by crossing heterozygous plaid stripes individuals (genotype Ps/ls), the recessive trait 'lengthwise stripes' will be observed (again) in a proportion of 3:1.
In this case:
- P >> lengthwise stripes x plaid stripes
- F1 >> 100% plaid stripes
- F2 >> plaid stripes (75%) and lengthwise-stripes (25%)
Learn more about Mendelian inheritance here:
brainly.com/question/25301436
Answer:
The tissue part is cells that are together. They are prokaryotic cells.
Explanation:
internal-organ function, breathing, digestion, and heartbeat. This system consists of two complementary parts: the sympathetic and parasympathetic systems.
There is a 1:4 chance of getting JjQq. The parent JjQq can produce four genotypes: JQ, Jq, jQ, and jq. the parent JJQq can produce two genotypes: JQ and Jq. When we do a punnett square:
JJQQ, JJQq, JjQQ, JjQq,
JJQq, JJqq, JjQq, and Jjqq
There are two JjQq.
Two out of eight is one out of four.
