D. Not enough info
Angles N and P are supplementary (125º + 55º = 180º) but this doesn't tell us anything about the measures of angles M and Q. The edge MQ of the quadrilateral is not guaranteed to be parallel to NP.
For example, we can move vertex M anywhere along MN and still preserve the measures of angles N and P.
Answer:
<em>h</em><em> </em><em>(</em><em>x</em><em>)</em><em> </em><em>=</em><em> </em><em>f</em><em> </em><em> </em><em>(</em><em>x</em><em>)</em><em>.</em><em>g</em><em> </em><em>(</em><em>x</em><em>)</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em> </em><em>(</em><em>-</em><em>2</em><em>)</em><em>(</em><em>5x</em><em>-</em><em>6</em><em>)</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>-</em><em>10</em><em>x</em><em> </em><em>+</em><em> </em><em>12</em>
<em>#</em><em>$</em><em>#</em><em> </em><em>THANK</em><em> </em><em>YOU</em><em> </em><em>#</em><em>$</em><em>#</em>
I think its saying find a side that has no numbers or has a letters. figure out the whole shape then subtract the sides we do know and theres your answer. And if its a decimal round the decimal to the nearest tenth
Answer:
A Type I error would occur if there was no evidence of an improvement on the national exam but there really was improvement.
Step-by-step explanation:
A type 1 error simply occurs when we incorrectly reject a true null hypothesis. In the scenario above, An experiment was conducted in other it know if there is sufficient evidence to support a claim that a new teaching method developed improves students score. If this claim is actually true in the real sense. However, after conducting a statistical test, we conuded that there was no sufficient evidence to support her claim of improvement using the new method, hence, the claim was rejected. By rejecting the claim, a true null has been rejected. Hence, a type 1 error has been committed.
<span>let y = sec^2 ( pi x )
y' = 2 sec ( pi x ) sec( pi x ) tan ( pi x ) pi
y' = 2pi sec^2 ( pi x ) tan ( pi x )
y''= 2pi sec^2 ( pi x ) * sec^2 ( pi x ) * pi + 2pi tan ( pi x ) * 2pi sec^2 ( pi x ) tan ( pi x )
y'' = 2 pi^2 sec^4 ( pi x ) + 4 pi^2 sec^2 ( pi x ) tan^2 ( pi x )</span>
