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2 years ago

Please help me with this homework

Mathematics

1 answer:

dimulka [17.4K]2 years ago

8 0

Answer:

Step-by-step explanation:

49 - 37 = 12

It takes 12 jumps to get from 37 (a) to 49 (c)

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The following two-way table describes student's

guajiro [1.7K]

P ( work/ senior ) = 0.14

The attached table

required

P ( work/ senior )

This is calculated using:

P ( work/ senior ) = n ( work/ senior )/ n ( senior ).

n ( work/ senior ) = 5

n ( senior ) = 25 + 5 + = 35

So:

P ( work/ senior ) = 5/35

P ( work/ senior ) = 0.14

Add 25+5+5 (because that is all the numbers in the 'Seniors' row) and then take the 5 that is in the 'Work' column and put that over 25. (5/25 fraction as a percent is 14).

Learn more about probability at

brainly.com/question/24756209

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7 0

1 year ago

Please help I'm almost done with this course I just need a few more answered

iogann1982 [59]

The answer would be B.

Hope this helped :)

6 0

2 years ago

There are 48 different animals pictured in Jorge's book. If 1/3 of them are herbivores how many herbivores?

Stolb23 [73]

16. 48 divided by 3 is 16

8 0

2 years ago

Read 2 more answers

Q6. (15 points) IQ examination scores of 500 members of a club are normally distributed with mean of 165 and SD of 15.

melamori03 [73]

Answer:

a) 0.8413

b) 421

c) $P_{95} = 189.675$

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 165

Standard Deviation, σ = 15

We are given that the distribution of IQ examination scores is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(IQ scores at most 180)

P(x < 180)

$P( x < 180) = P( z < \displaystyle\frac{180 - 165}{15}) = P(z < 1)$

Calculation the value from standard normal z table, we have,

$P(x < 180) = 0.8413 = 84.13\%$

b) Number of the members of the club have IQ scores at most 180

n = 500

$\text{Members} = n\times \text{P(IQ scores at most 180)}\\= 500\times 0.8413\\=420.65 \approc 421$

c) P(X< x) = 0.95

We have to find the value of x such that the probability is 0.95

$P( X < x) = P( z < \displaystyle\frac{x - 165}{15})=0.95$

Calculation the value from standard normal z table, we have,

$P(z < 1.645) = 0.95$

$\displaystyle\frac{x - 165}{15} = 1.645\\\\x = 189.675$

$P_{95} = 189.675$

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3 years ago

Thirty work orders are selected from a filing cabinet containing 500 work order folders by choosing every 15th folder. which sam

Andru [333]

It is Systematic sampling

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3 years ago