First we find the slope by using the slope formula : (y2 - y1) / (x2 - x1)
slope = (y2 - y1) / (x2 - x1)
(0,7)....x1 = 0 and y1 = 7
(8,-2)...x2 = 8 and y2 = -2
now sub...pay attention to ur signs
slope = (-2 - 7) / (8 - 0) = -9/8
now we use y = mx + b
slope(m) = -9/8
u can use either of ur points...(0,7)...x = 0 and y = 7
now sub into ur formula and find b, the y int
7 = -9/8(0) + b
7 = b
so ur equation is : y = -9/8x + 7 <==
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
Answer:
1. Choice B
2. Choice C
3. X=-2
4. Choice A
5. y = 5/2 x + 5
Step-by-step explanation:
1.
the slope is down 3 over 2 m =-3/2
point slope form
y-y1= m (x-x1)
y-y1 = -3/2 (x-x1)
Choice B
2. (-3,-1) (1/2,2)
slope = (y2-y1)/(x2-x1)
m=(2--1)/(1/2--3) = (2+1)/(1/2+3) = 3/(3.5) = multiply top and bottom by 2
m = 6/7
point slope form
y-y1 = m(x-x1)
y--1 = 6/7 (x--3)
y+1 =6/7 (x+3)
multiply by 7
7y+7 = 6(x+3)
7y+7 = 6x+18
subtract 7y from each side
7 = 6x-7y+18
subtract 18 from each side
-11=6x-7y
Choice C
3. x=-2
This is a vertical line, the value of x never changes
4. (-1,2) (1,-4)
slope =(y2-y1)/(x2-x1)
= (-4-2)/(1--1) = -6/(1+1) = -6/2 = -3
point slope form
y-y1 = m(x-x1)
y-2 = -3(x--1)
y-2 = -3(x+1)
y-2 = -3x-3
add 2 to each side
y = -3x-1
Choice A
5. (-2,0) (0,5)
the y intercept is 5
slope is change in y over change in x
slope =(y2-y1)/(x2-x1) = (0-5)/(-2-0) = -5/-2 = 5/2
slope intercept form
y= mx+b
y = 5/2 x + 5
