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wariber [46]
4 years ago
9

The Correct Answer Is?

Mathematics
1 answer:
Alekssandra [29.7K]4 years ago
8 0
Hello!

n<span>≤-1/2 means that n is less than the open circle, because an open circle means the variable can not be equal to that point. so your answer is: D

I hope this helps, and have a nice day.
</span>
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Circle the GCF of 28x3 and<br> 16x2y2<br> 28x3: 2.2.7.*•*•*<br> 16x2y2:2.2.2.2.x.x.y.y
Sedaia [141]

Answer:

Step-by-step explanation:

28x^3 = 2 * 2 * 7 * x * x * x

16x^2Y^2 = 2 * 2 * 2 * 2 * x * x * y *y

GCF = 2 * 2 * x *x = 4x^2

Circle which are in both

4 0
3 years ago
Which description best compares the graphs given by the equations: x-5y=-5 5x-25y=75
yulyashka [42]

Considering the slopes of the given lines, they are parallel lines.

<h3>When are lines parallel, perpendicular or neither?</h3>

The slope, given by <u>change in y divided by change in x</u>, determines if the lines are parallel, perpendicular, or neither, as follows:

  • If they are equal, the lines are parallel.
  • If their multiplication is of -1, they are perpendicular.
  • Otherwise, they are neither.

The first line, in standard form, is given by:

5y = x + 5

y = 0.2x + 1.

The slope is of m = 0.2.

For the second line, we have that:

25y = 5x - 75

y = 0.2x - 3

The slope is of m = 0.2.

Same slope, hence the lines are parallel.

More can be learned about the slope of a line at brainly.com/question/12207360

#SPJ1

4 0
2 years ago
Same question just with picture
-BARSIC- [3]

Answer:

between 4 and 10

Step-by-step explanation:

just multiply lma.o

3 0
4 years ago
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
What important lesson does Ruri learn from her mother in “The Bracelet”? (brainy)
steposvetlana [31]
I think your answer is the last one, to treasure memories rather than material goods.
8 0
3 years ago
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