Answer:
light takes 3×10^5 second s
so total seconds taken by the light =780×10^6/3×10^5
1 min=60sec
no. of min=2600/60
=43333min
Answer: Thus, the number with the larger value of 8 is 184.36 and it is 100 times larger.
Step-by-step explanation:
First we can find out the place value,
Then we can write,
Define Place value :
Place value is the basis of our entire number system. This is the system in which the position of a digit in a number determines its value. The number 42,316 is different from 61,432 because the digits are in different positions.
[or]
Place value of a digit can be defined as the position of the particular digit in a given number.
For Example :
The place value of 7 in 1870 is 70
Given the data,
First we use digit is : 184.36
Second we use digit is : 9027.83
Place value of 8 in First digit is ⇒ 184.36 is 80
Place value of 8 in Second digit is ⇒ 9027.83 is 0. 8
We can solve the Ratio is :
Ratio = 80/ 0.8
Ratio = 100 times
Therefore,
Thus, the number with the larger value of 8 is 184.36 and it is 100 times larger.
Learn more about event correlation here: brainly.com/question/17103145
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Answer:
$70,201.38
Step-by-step explanation:
To determine the principal amount, we can use the formula:

A = $200,000
r = 7% or 0.07
t = 15 years
n = 12
Now let's substitute our values.



So the principal needed to get 200,000 in 15 years is $70,201.38.
<h2>Answer: slope = ¹¹/₁₃
</h2><h3>Step-by-step explanation: </h3>
The question gives us two points, (−13, −19) & (13, 3), from which we can find the slope and later the equation of the line.
Finding the Slope
The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)
= ((3 - (-19)) ÷ (13 - (-13))
= 22 ÷ 26
= ¹¹/₁₃
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<em>Checking my answer:</em>
<em>We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line. If the line passes through both of the points then we calculated the slope correctly.</em>
⇒ y + 19 = ¹¹/₁₃ (x + 13)
<em>I have included a Desmos Graph that I graphed using the information equation (including the slope) and the points given. </em>