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vodka [1.7K]
3 years ago
15

Given sec theta=-4/3 and 90°

Mathematics
1 answer:
hoa [83]3 years ago
3 0

Answer:

Option A.

Step-by-step explanation:

It is given secθ = - \frac{4}{3}

then cosθ = -\frac{3}{4}

Now we know the identity

sinθ = \sqrt{1-cos^{2}\theta }

       = \sqrt{1-(-\frac{3}{4} )^{2}}

       = \frac{\sqrt{7} }{4}

Now sin2θ = 2sinθcosθ

Now we put the values of cosine and sine in the formula

sin2θ = 2×(-\frac{3}{4})(\frac{\sqrt{7}}{4})

         = -\frac{3\sqrt{7}}{8}

Therefore, option A. is the answer.

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6 0
3 years ago
How do u solve (2d-5)/2 = (5d+2)/9
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