Answer:
;;6
Step-by-step explanation:
56 5
Step-by-step explanation:
3/2(4x-1)-3x = 5/4-(x+2)
6x -3/2 -3x = 5/4 -x -2
3x -3/2 = 5/4-2-x
4x=5/4 -2 +3/2
4x= (5-8+6)/4
4x=3/4
x=3/16
Answer: A. A=(1000-2w)*w B. 250 feet
C. 125 000 square feet
Step-by-step explanation:
The area of rectangular is A=l*w (1)
From another hand the length of the fence is 2*w+l=1000 (2)
L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.
Express l from (2):
l=1000-2w
Substitude l in (1) by 1000-2w
A=(1000-2w)*w (3) ( Part A. is done !)
Part B.
To find the width w (Wmax) that corresponds to max of area A we have to dind the roots of equation (1000-2w)w=0 ( we get it from (3))
w1=0 1000-2*w2=0
w2=500
Wmax= (w1+w2)/2=(0+500)/2=250 feet
The width that maximize area A is Wmax=250 feet
Part C. Using (3) and the value of Wmax=250 we can write the following:
A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets
Answer:
y = (x -5)² + 3.
Step-by-step explanation:
Given : parabola with a vertex at (5,3).
To find : Which equation has a graph that is a parabola.
Solution : We have given vertex at (5,3).
Vertex form of parabola : y = (x -h)² + k .
Where, (h ,k ) vertex .
Plug h = 5 , k= 3 in vertex form of parabola.
Equation :y = (x -5)² + 3.
Therefore, y = (x -5)² + 3.
Answer:
exactly one, 0's, triangular matrix, product and 1.
Step-by-step explanation:
So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.
"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries. Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).
Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.