All categories

2 years ago

1 7/8 * 3 in a fraction form

Mathematics

2 answers:

Blizzard [7]2 years ago

8 0

5 5/8

because 1 7/8*3 =45/8 which equals 5 5/8

Radda [10]2 years ago

7 0

Simplify the expression :

Exact form:

51/8

Decimal form :

6.375

Mixed number form:

6 3/8

Hope this help :)

Have A great day!

You might be interested in

What is the first step in solving the equation Two-thirds x + one-third x + 2 = 5?

Shkiper50 [21]

Answer:

combine like terms.

Step-by-step explanation:

none of the other answers seem correct.

3 0

2 years ago

Read 2 more answers

Write an algebraic equation that models the following statement.

8_murik_8 [283]

2(x +4)-6(q/9)

The slash represents a division sign.

5 0

2 years ago

I need to find x pls

Rainbow [258]

I hope this helps you

3 0

2 years ago

Time spent using e-mail per session is normally distributed, with mu equals 11 minutes and sigma equals 3 minutes. Assume that

liq [111]

Answer:

a) 0.259

b) 0.297

c) 0.497

Step-by-step explanation:

To solve this problem, it is important to know the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 11, \sigma = 3$

a. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 25, s = \frac{3}{\sqrt{25}} = 0.6$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.6}$

$Z = 0.33$

$Z = 0.33$ has a pvalue of 0.6293.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.6}$

$Z = -0.33$

$Z = -0.33$ has a pvalue of 0.3707.

0.6293 - 0.3707 = 0.2586

0.259 probability, rounded to three decimal places.

b. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 10.5 and 11 minutes?

Subtraction of the pvalue of Z when X = 11 subtracted by the pvalue of Z when X = 10.5. So

X = 11

$Z = \frac{X - \mu}{s}$

$Z = \frac{11 - 11}{0.6}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

X = 10.5

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.5 - 11}{0.6}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033.

0.5 - 0.2033 = 0.2967

0.297, rounded to three decimal places.

c. If you select a random sample of 100 sessions, what is the probability that the sample mean is between 10.8 and 11.2 minutes?

Here we have that $n = 100, s = \frac{3}{\sqrt{100}} = 0.3$

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{11.2 - 11}{0.3}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486.

X = 10.8

$Z = \frac{X - \mu}{s}$

$Z = \frac{10.8 - 11}{0.3}$

$Z = -0.67$

$Z = -0.67$ has a pvalue of 0.2514.

0.7486 - 0.2514 = 0.4972

0.497, rounded to three decimal places.

5 0

2 years ago

PLZ HELP I BEG YOU ITS URGENT

harkovskaia [24]

Answer:

$638.25

Step-by-step explanation:

The interest is 5.5% yearly and it is simple interest.

Now, if we consider a deposit of $575 into the bank account that earned 5.5% simple interest each year, then after 2 and half years James will get interest only for 2 years as the 3rd year's interest will be added after the 3rd year.

Therefore, if no money was deposited into or withdrawn from the account, then after 2.5 years the sum will be

$575(1 + \frac{5.5 \times 2}{100}) = 638.25$ dollars. (Answer)

7 0

2 years ago

1 7/8 * 3 in a fraction form ​

1 7/8 * 3 in a fraction form