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sergij07 [2.7K]
3 years ago
15

Question 3 A study was performed to determine whether men and women differ in their repeatability in assembling components on pr

inted circuit boards. Random samples of 25 men and 21 women were selected, and each subject assembled the units. The two sample standard deviations of assembly time were s Subscript men Baseline equals 0.98 minutes and s Subscript women Baseline equals 1.02 minutes. (a) Is there sufficient evidence to support the claim that men and women differ in repeatability for this assembly task at the 0.02 level of significance
Mathematics
1 answer:
Fed [463]3 years ago
7 0

Answer:

There is no sufficient evidence to support the claim that men and women differ in repeatability for this assembly task

Step-by-step explanation:

Given

Let subscript 1 represent men and 2 represent women, respectively.

n_1 = 25

n_2 = 21

s_1 = 0.98

s_2 = 1.02

\alpha = 0.02

Required

Determine if here is enough evidence

First, we need to state the hypotheses

H_o: \sigma_1^2 = \sigma_2^2

H_1: \sigma_1^2 \ne \sigma_2^2

Next, calculate the test statistic using:

F = \frac{s_1^2}{s_2^2}

F = \frac{0.98^2}{1.02^2}

F = 0.923

Calculate the rejection region;

But first, calculate the degrees of freedom

df_1 =n_1 - 1

df_1 =25 - 1

df_1 =24

df_2 = n_2 -1

df_2 = 21 - 1

df_2 = 20

Using the F Distribution:  table

c = \frac{\alpha}{2}

c = \frac{0.02}{2}

c = 0.01

At 0.01 level (check row 20 and column 24), the critical value is:

<em></em>f_{0.01,24,20} = 2.86<em> --- the upper bound</em>

At 0.01 level (check row 24 and column 20), the critical value is:

f_{0.01,20,24} = 2.74

Calculate the inverse F distribution.

f_{0.99,20,24} = \frac{1}{f_{0.01,20,24}} = \frac{1}{2.74} =0.365 ---- the lower bound

The rejection region is then represented as:

0.365 < Test\ Statistic < 2.86

If the test statistic falls within this region, then the null hypothesis is rejected

F = 0.923 --- Test Statistic

0.365 < 0.923 < 2.86

<em>The above inequality is true; so, the null hypothesis is rejected.</em>

<em>This implies that, there is no sufficient evidence.</em>

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Answer:

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Step-by-step explanation:

Angle with the horizontal, θ =25°

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3 years ago
A cinema can hold 270 people at one performance 5/9 of the seats were occupied of the occupied seats 40% we occupied by concessi
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Question:

A cinema can hold 270 people at one performance 5/9 of the seats were occupied of the occupied seats 40% we occupied by concessionary ticket holders.

What is the number of seats occupied by concessionary ticket holders?.

Answer:

60 seats

Step-by-step explanation:

Given

Number of seats = 270

Occupied Seats = 5/9

Concessionary ticket holders = 40% of occupied Seats

Required

The number of seats occupied by concessionary ticket holders

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