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posledela
3 years ago
13

Of the 103 people enrolled in mathematics class, 91% are present. How many are present?

Mathematics
2 answers:
Damm [24]3 years ago
7 0
Just find the 91% of 103

103 * 91% = 103 * 0.91 = 93.73

About 94 are present from the 103 people

Hope this helps :)

LenKa [72]3 years ago
6 0

Answer:

93 people.

Step-by-step explanation:

We have been given that of the 103 people enrolled in mathematics class, 91% are present.

To find the number of people present we have to find 91% of 103.

\text{Number of people present}=\frac{91}{100}\times 103

\text{Number of people present}=0.91\times 103

\text{Number of people present}=93.73\approx 93

Since we can not have 0.73 of a person, therefore, 93 people are present.

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50 Points
ANEK [815]

Answer:

x=5

Step-by-step explanation:

First you have to solve for y. Since it is a isoceles triangle, the two base angles are equal. You dont even need to solve for y because both of them will equal 73. Now you know two of the angles are 73 degrees, 146 in total. Since you know the total degrees in a triangle is 180, set up an equation that is adding all the angles to equal 180. Then solve for x.

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How do you answer this
Sedbober [7]
you just need to multiply the length times width
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