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3 years ago

Factor over complex number y^4+12y^2+36

1 answer:

3 0

$((y^4) + (2^2*3y^2)) + 36 \\ \\ Factoring \ y^4+12y^2+36 \\ \\ y^4 + 6y^2 + 6y^2 + 36 \\ \\ y^2 * (y^2+6) \\ \\ 6 * (y^2+6) \\ \\ (y^2+6) * (y^2+6) \\ \\ Multiply \ (y^2+6) \ by \ (y 62+6) \\ \\ YOUR \ ANSWER: \ \boxed{ (y^2 + 6)^2}


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Qual a raiz da equação X²+5X-14=0 ?

ElenaW [278]

Answer:

e) Hence 2, -7 are roots of the equation X² + 5X - 14 = 0

Step-by-step explanation:

given equation : X² + 5X - 14 = 0

⇒ X² + 7X - 2X - 14 = 0

⇒ X·(X + 7) - 2·(X + 7) = 0

⇒ (X + 7)·(X - 2) = 0

⇒ X = -7, X = 2

Hence 2, -7 are roots of the equation X² + 5X - 14 = 0

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3 years ago

What is 80+x=200 also, meet my friend group

dedylja [7]

$\huge\text{Hey there!}$

$\huge\textsf{80 + x = 200}$

$\huge\textsf{x + 80 = 200}$

$\huge\text{SUBTRACT 80 to BOTH SIDES}$

$\huge\textsf{x + 80 - 80 = 200 - 80}$

$\huge\text{CANCEL out: 80 - 80 because that gives you 1}$

$\huge\text{KEEP: 200 - 80 because that helps for x}$

$\huge\textsf{x = 200 - 80}$

$\huge\textsf{200 - 80 = x}$

$\huge\textsf{x = 120}$

$\boxed{\boxed{\huge\textsf{Therefore, your answer x = \bf 120}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\huge\text{Amphitrite1040:)}$

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Alex777 [14]

The first one and the last one are correct.

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Substitute 8 for x and evaluate the expression below. 5(x + 1) - 20

fenix001 [56]

Answer:

Step-by-step explanation:

Substituting x = 8 into the expression

5(8 + 1) - 20

= 5(9) - 20

= 45 - 20

= 25

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AURORKA [14]

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