3 years ago

Factor over complex number y^4+12y^2+36

1 answer:

3 0

$((y^4) + (2^2*3y^2)) + 36 \\ \\ Factoring \ y^4+12y^2+36 \\ \\ y^4 + 6y^2 + 6y^2 + 36 \\ \\ y^2 * (y^2+6) \\ \\ 6 * (y^2+6) \\ \\ (y^2+6) * (y^2+6) \\ \\ Multiply \ (y^2+6) \ by \ (y 62+6) \\ \\ YOUR \ ANSWER: \ \boxed{ (y^2 + 6)^2}


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