<img src="https://tex.z-dn.net/?f=10%20%5Cdiv%20%20%5Csqrt%7B6x%7D%20" id="TexFormula1" title="10 \div \sqrt{6x} " alt="10 \div

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scZoUnD [109]

3 years ago

\sqrt{6x} " align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Aliun [14]3 years ago

8 0

The answer is what the guy below me said

Oxana [17]3 years ago

3 0

Unfortunately, you haven't shared the instructions. My guess is that you were supposed to "rationalize the denominator," that is, remove the radical from the denominator.

10 sqrt(6x) 10sqrt(6x)
------------ * ------------- = ----------------
sqrt(6x) sqrt(6x) 6x

This is the correct form of the answer; it has no radical in the denominator.

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Jackie bought a 3-pack of tubes of glue. She used 0.27 ounce of the glue from the 3-pack

brilliants [131]

Answer:

0.54 ounces in each tube

Step-by-step explanation:

Add the amount she used so we can add it in. 1.35+0.27= 1.62. Then divide it by the number of tube and since it was a 3 pack you divide it by 3. 1.62/3=0.54 so there is 0.54 ounces in each tube.

5 0

3 years ago

Read 2 more answers

Does anyone know the answer?

motikmotik

Answer:

We conclude that the area of the right triangle is:

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