One line passes through the points (-2,3) and (0,-3) , it means the y intercept is b=-3
and slope m = 

So the equation of line will be 
And the inequality should be 
Or 
And the other line passes through (-2,3) and (0,2)
So the y intercept is b=2
and the slope is 
So the equation of line will be 
Or

So answer is 
Mr. chang paid the least because 10% off 25 is more than 20%off 30
Option C: -3 is the average rate of change between
and 
Explanation:
The formula to determine the average rate of change is given by
Average rate of change = 
We need to find the average rate of change between
and 
Thus, from the table, we have,
, 
, 
Thus, substituting these values in the formula, we get,
Average rate of change = 


Thus, the average rate of change between
and
is -3.
Hence, Option C is the correct answer.
If period of

is one-half the period of

and
<span>

has a period of 2π, then

and

.
</span>
To find the period of sine function

we use the rule

.
<span /><span />
f is sine function where f (0)=0, then c=0; with period

, then

, because

.
To find a we consider the condition

, from where

.
If the amplitude of

is twice the amplitude of

, then

has a product factor twice smaller than

and while period of

<span> </span> is 2π and g(0)=0, we can write

.
Change the mixed numbers into improper fractions:
5/3 X 9/2
Reduce - the 3 and 9 can be simplified
5/1 X 3/2
multiple numerators and denominators
15/2
Not sure how you need the answer - i would change it into a mixed number
7 1/2