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scZoUnD [109]
3 years ago
8

\sqrt{6x} " align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Aliun [14]3 years ago
8 0
The answer is what the guy below me said
Oxana [17]3 years ago
3 0
Unfortunately, you haven't shared the instructions.  My guess is that you were supposed to "rationalize the denominator," that is, remove the radical from the denominator.

  10              sqrt(6x)       10sqrt(6x)
------------ * ------------- = ----------------
sqrt(6x)        sqrt(6x)              6x

This is the correct form of the answer; it has no radical in the denominator.
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Which of the following shows a relationship of 4,000 as ten times greater than 400?
stira [4]
400 times ten because when you multiply you get 40,000.
8 0
3 years ago
PLEASE HELP! 20 POINTS 1) A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the
drek231 [11]

Answer:

1) The height of the ball from 0 to 5  seconds are;

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2)  The correct option is;

D. -16·t² + 25·t + 1

Step-by-step explanation:

1) The equation of motion of the ball is given as follows;

H(t) = -4.9·t² + 25·t + 2

The height of the ball from 0 to 5 seconds are;

H(0) = -4.9×(0)² + 25×(0) + 2 = 2

H(1) = -4.9×(1)² + 25×(1) + 2 = 22.1

H(2) = -4.9×(2)² + 25×(2) + 2 = 32.4

H(3) = -4.9×(3)² + 25×(3) + 2 = 32.9

H(4) = -4.9×(4)² + 25×(4) + 2 = 23.6

H(5) = -4.9×(5)² + 25×(5) + 2 = 4.5

Therefore, we have;

The height of the ball are

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) Given that the equation of the ball is that of a projectile motion, such as follows;

h = h₀ + v₀·sin(θ₀)·t - 1/2·g·t² which is equivalent to h = -1/2·g·t²+ h₀+v₀·sin(θ₀)·t

it is best represented by the quadratic equation of an upside down parabola which is option D. -16·t² + 25·t + 1

6 0
3 years ago
On a coordinate plane, triangle A B C and parallelogram G H J K are shown. Triangle A B C has points (2, 0), (1, negative 6), (n
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Answer:

The area of △ABC is 2 square units greater than the area of parallelogram GHJK.

Step-by-step explanation:

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$700 principal earning 5%, compounded monthly, after 9 years
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1,096.79
because 
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