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umka21 [38]
3 years ago
10

The path of a football can be modelled by the equation, h=-10d2+120d , where h represents the height, in metres, of the football

above the ground and d represents the horizontal distance, in metres, of the football from the player. At what horizontal distance does the football land?
Mathematics
1 answer:
Marta_Voda [28]3 years ago
3 0

Answer:

12 m

Step-by-step explanation:

The path of a football has been modeled by the equation:

h= -10d^2+120d

where h represents the height and d represents the horizontal distance.

When the ball lands, it means that its height is back at 0 metres. This means that we have to find horizontal distance, d, when height, h, is 0.

=> 0= -10d^2+120d

=> 10d^2 - 120d = 0

d(10d - 120) = 0

∴ d = 0 m

and

10d - 120 = 0

=> d = 120 / 10 = 12 m

There are two solutions for d when h = 0 m.

The first solution (d = 0 m) is a case where the ball has not been thrown at all. This means the ball has not moved away from the football player and it is still on the ground.

The second solution is the answer to our problem (d = 12 m). The ball lands at a horizontal distance of 12 m

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Answer:

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Step-by-step explanation:

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Check your work

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If the sides of two similar triangles are in the ratio of 3:5, find the ratio of their areas.
Kazeer [188]

Ratio of areas of similar triangles is 9 : 25.

Solution:

Given data:

Ratio of sides of two similar triangles = 3 : 5

To find the ratio of areas of the triangles:

We know that,

<em>In two triangles are similar, then the ratio of their area is equal to the square of the ratio of their sides.</em>

$\text{Ratio of areas} = \frac{\text{Area of triangle 1}}{\text{Area of triangle 2} }

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Ratio of areas of similar triangles is 9 : 25.

5 0
3 years ago
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7 0
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Refer to the table below if needed.
elena-14-01-66 [18.8K]

A quadrant is the area that is divided into the x and y axes

The quadrants in which tan \theta and cot \theta are positive are I and III

<h3>How to determine the quadrants</h3>

The tangent of an angle is calculated as:

\tan(\theta) = \frac{sin(\theta)}{\cos(\theta)}

While the cotangent of the angle is calculated as:

\cot(\theta) = \frac{cos(\theta)}{\sin(\theta)}

The above equations mean that:

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Hence, the quadrants in which tan \theta and cot \theta are positive are I and III

Read more about trigonometry ratios at:

brainly.com/question/8120556

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