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monitta
3 years ago
13

Use elimination method to solve 5x+y=-10 7x-3y=-36

Mathematics
1 answer:
k0ka [10]3 years ago
7 0
5x+y=-10\\ \\ 7x-3y=-36

Let's multiply the first equation by 3. (As you can see y's coefficient in the first one is 1 and in the second one is -3 , we will multiply the first equation by 3 so when we add the equations their sum will be 0)

3\cdot (5x+y)=3\cdot -10\\ \\ 15x+3y=-30

Now let's add this new equation and our second equation.

7x-3y=-36\\ \\ 15x+3y=-30\\ \\ (15x+3y)+(7x-3y)=(-30)+(-36)\\ \\ 15x+7x+3y-3y=-30-36\\ \\ 22x=-66\\ \\ x=\frac { -66 }{ 22 } \\ \\ x=-3

We found x=-3

Now let's plug x's value in one of the equations to find y's value.

x=-3\\ \\ 5x+y=-10\\ \\ 5\cdot -3+y=-10\\ \\ -15+y=-10\\ \\ y=-10+15\\ \\ y=5

So we found y=5

Solution ;

(-3, 5)

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Answer:

For a sale value greater than $7200 the plan a is profitable.

Step-by-step explanation:

Let us assume for a sale of $x, Chris will choose plan a.

Now, in plan a, a commission of 8% of sales and $370 per month, is the salary.

So, for a sale of $x the salary is $(370 + 0.08x) per month.

And, in plan b, a commission of 3% of sales and $730 per month, is the salary.

So, for a sale of $x the salary is $(730 + 0.03x) per month.

Now, for selecting plan a, the condition is  

(370 + 0.08x) > (730 + 0.03x)

⇒ 0.05x > 360

⇒ x > 7200

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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