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2 years ago

Can someone solve this?

Mathematics

1 answer:

inn [45]2 years ago

6 0

Answer:

1. 15 degrees.

2. 90 degrees.

3. 66 degrees.

Step-by-step explanation:

M and 2 appear to be 90 degrees. This is because there are parallel sides on the left and right of the kite. So, 2 is 90 degrees.

E and 75 are corresponding (I don't remember the postulate or whatnot) so 90 degrees plus 75 degrees is 165 degrees. There are 180 degrees in a triangle, so 180 minus 165 is 15. 1 Has to be 15 degrees.

3 is 66 degrees since it is corresponding with the angle on the other side of T (I, once again, do not remember the postulate).

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Performance task A parade route must start And and at the intersections shown on the map. The city requires that the total dista

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Answer:

A: the proposed route is 3.09 miles, so exceeds the city's limit

Step-by-step explanation:

The length of the route in grid squares can be found using the Pythagorean theorem on the two parts of the route. Let 'a' represent the length of the route to the park from the start, and 'b' represent the route length from the park to the finish. Then we have (in grid squares) ...

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2 years ago

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2 years ago

Read 2 more answers

A top-loading washing machine has a cylindrical basket that rotates about a vertical axis. The basket of one such machine starts

damaskus [11]

Answer:

$n_{tot}=44rev$

Step-by-step explanation:

In order to solve this problem we can make use of the following formula:

$\theta=(\frac{\omega_{f}+\omega_{0}}{2})t$

where θ is the total angle the basket has turned, ω is the angular velocity and t is the time.

Generally theta is written in radians and omega is written in radians per second. Now, since the revolutions are directly related to the radians and they want us to write our answer in revolutions, we can directly use the provided speeds in the formula, so we can rewrite it as:

$n=(\frac{f_{f}+f_{0}}{2})t$

where n represents the number of revolutions and f is the frequency at which the basket is turning.

The movement of the cylindrial basket can be split in two stages, when it accelerates and when it decelerates. So let's analye the first stage:

$n=(\frac{4rev/s+0}{2})(9s)=18rev$

and now let's analyze the second stage, where it decelerates, so we get:

$n=(\frac{0rev/s+4rev/s}{2})(13s)=26rev$

So now that we know how many revolutions the cylindrical basket will take as it accelerates and as it decelerates we can add them to get:

n=18rev+26rev=44rev

So the basket will turn a total of 44 revolutions during this 22s interval.

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2 years ago