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Semenov [28]
4 years ago
15

Jessica has two strings. the first string measures 80 cm and the second string measures 64cm. she wants to cut the strings into

equal lengths. of the least number of strings equal length is 16 what is the length of each string
Mathematics
1 answer:
omeli [17]4 years ago
5 0
<span>The highest common denominator between 80 and 64 is 16. This means no string can be cut longer than 16 inches for them all to have the same length.</span>
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There are 4 questions thank you for helping me
GenaCL600 [577]

Answer: question #1 ~ there are 50 boys

Step-by-step explanation:

10:11

X:55

11 was multiplied by 5 so you have to do the same for 10

3 0
3 years ago
Mason walked on Monday, Wensday, and Friday. Use these clues to find how far he walked each day. These distances were six-eights
krok68 [10]

Answer:

Monday he walked \frac{1}{4}miles

Wednesday he walked \frac{6}{8}miles

Friday he walked \frac{1}{6}miles

Step-by-step explanation:

Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.

distances are \frac{6}{8}, \frac{1}{4}, \frac{1}{6} that are 0.75, 0.25 and 0.17 respectively.

Now, he didn't walk farthest on Monday and also walked less on Friday than Monday.

∴ Less distance travelled is \frac{1}{6} which is on friday and then \frac{1}{4} on monday.

Rest distance which is \frac{6}{8} on wednesday.

Hence, Monday he walked \frac{1}{4}miles

Wednesday he walked \frac{6}{8}miles

Friday he walked \frac{1}{6}miles

4 0
4 years ago
Read 2 more answers
Triangle ABC is similar to triangle WYZ.
11Alexandr11 [23.1K]
I think true I am not sure
6 0
3 years ago
There are 3 times as many pears are oranges. If a group of children receive 5 oranges each,there will be no left over.If the sam
lozanna [386]

There are 15 oranges

<em><u>Solution:</u></em>

Let "x" be the number of oranges

Let "y" be the number of pears

Let "c" be the number of children

<em><u>There are 3 times as many pears are oranges</u></em>

Number of pears = 3 times the number of oranges

y = 3x -------- eqn 1

<u><em>If a group of children receive 5 oranges each, there will be no left over</em></u>

So, "c" children receives 5 oranges each, there will be no left over

number of oranges = 5(number of children)

x = 5c ------- eqn 2

<em><u>If the same group of children receive 8 oranges each, there will be 21 pears left over</u></em>

number of pears = 8 oranges(number of children) + 21

y = 8c + 21

<em><u>Substitute eqn 1</u></em>

3x = 8c + 21 ---- eqn 3

<em><u>Substitute eqn 2</u></em>

3(5c) = 8c + 21

15c - 8c = 21

7c = 21

c = 3

<em><u>Substitute c = 3 in eqn 2</u></em>

x = 5(3)

x = 15

Thus there are 15 oranges

6 0
3 years ago
Read 2 more answers
Simplify:
OlgaM077 [116]
   4x + 5                          5x                     4x + 5 - 5x                 -x + 5
----------------     -      ----------------     =     ------------------   =  -------------------
6x^2 - x - 12             6x^2 - x - 12            6x^2 - x - 12           6x^2 - x - 12

8 0
3 years ago
Read 2 more answers
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