Answer:
a) 
b) Approx. 27,569 bacteria
c) About 103 minutes
Step-by-step explanation:
a)
This will follow exponential modelling with form of equation shown below:

Where
A is the initial amount (here, 12000)
b is the growth factor (double, so growth factor is "2")
n is the number of minutes in which it doubles, so n = 50
Substituting, we get our formula:

b)
To get number of bacteria after 1 hour, we have to plug in the time into "t" of the formula we wrote earlier.
Remember, t is in minutes, so
1 hour = 60 minutes
t = 60
Substituting, we get:

The number of bacteria after 1 hour would approximate be <u>27,569 bacteria</u>
<u></u>
c)
To get TIME to go to 50,000 bacteria, we will substitute 50,000 into "y" of the equation and solve the equation using natural logarithms to get t. Shown below:

After about 103 minutes, there will be 50,000 bacteria