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Ronch [10]
3 years ago
12

Zeros are always considered significant digits when they are to the left of the decimal point

Physics
1 answer:
maksim [4K]3 years ago
7 0

Answer:

Zeros to the left of a decimal can be insignificant place holders, such as in 0.043 (two significant figures).

They can be significant if they are between two digits who themselves are significant, such as in 101.000 (three significant figures).

In the case of a number like 1,000 we can see there is only one significant figure. The zero digits are not between sigfigs.

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What parts of the body can be affected by musculoskeletal disorders?
adoni [48]

Answer:

Musculoskeletal disorders (MSD) are injuries or disorders of the muscles, nerves, tendons, joints, cartilage, and spinal discs.

Explanation:

3 0
2 years ago
How much force would you need to cause a 20-kilogram object to accelerate in a straight line to 20 m/s2?
Yakvenalex [24]

Answer:

400N

Explanation:

Newton's second law of motion

F = ma

20 x 20 = F

F = 400

5 0
2 years ago
In a given cartesian coordinate system a particle is in the position (initial vector position) ( 9.2 , 3.1 ) meters. After 10 se
vesna_86 [32]

Answer:

Thus, the average velocity is 9.73 m/s.

Explanation:

The velocity is given by the rate of change of position.  

initial position, A = (9.2, 3.1) m

final position, B = (72.2, 77.2) m

time, t = 10 s

The velocity is given by

\overrightarrow{v} =\frac{\overrightarrow{B}-\overrightarrow{A}}{t}\\\overrightarrow{v}=\frac{(72.2-9.2)\widehat{i} - (77.2-3.1)\widehat{j}}{10}\\\overrightarrow{v}=\frac{63 \widehat{i} - 74.1\widehat{j}}{10}\overrightarrow{v} =6.3 \widehat{i} - 7.41 \widehat{j}\\v =\sqrt{6.3^{2}+7.41^{2}}v = 9.73 m/s

6 0
2 years ago
4-What determines the length of a planet's day? *
shusha [124]

Answer:

Axis rotation to determine the length of a day

Explanation:

The length of time it takes a planet to complete one full rotation on it's axis is what we would measure as being one day. On Earth, it takes slightly less than 24 hours to rotate on its axis and this is one day.

7 0
3 years ago
What is the work done by gravity on a 4 kg ball
I am Lyosha [343]

Answer:

a. Work done = 313.92 Joules

b. Work done = 439.49 Joules

Explanation:

Work done = Force x distance

Where: Force = mass x gravity

Thus,

Work done = Force x gravity x distance

The earth's acceleration to gravity = 9.81 m/s^{2}.

a. The work done as it goes from B to A can be determined as;

work done = 4 x 9.81 x 8

                  = 313.92 Joules

b. The distance between A and C is the total horizontal distance covered from A to C.

i.e 8 + 3.2 = 11.2 m

The work done as the ball goes from point A to C can be determined as:

work done = 4 x 9.81 x 11.2

                  = 439.488

work done = 439.49 Joules

4 0
2 years ago
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