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Ronch [10]
3 years ago
12

Zeros are always considered significant digits when they are to the left of the decimal point

Physics
1 answer:
maksim [4K]3 years ago
7 0

Answer:

Zeros to the left of a decimal can be insignificant place holders, such as in 0.043 (two significant figures).

They can be significant if they are between two digits who themselves are significant, such as in 101.000 (three significant figures).

In the case of a number like 1,000 we can see there is only one significant figure. The zero digits are not between sigfigs.

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Why are computer simulations useful in studying phenomena in the universe?
kenny6666 [7]

Computer simulation is useful because it helps in the prediction of what will likely happen in the future using data from past events.

<h3>What is computer simulation?</h3>
  • This is the use of computer models to represents a hypothetical scenarios that are likely to be obtained in the real world.

Computer simulations are useful in studying phenomena in the universe because they help us to achieve the followings;

  • It helps in the prediction of what will likely happen in the future using data from past events.
  • It saves cost and time of carrying out actual experiments.
  • It can help prevent a disaster that may occur in the future.

Learn more about computer simulations here: brainly.com/question/22214039

5 0
2 years ago
The unit of energy is a derived unit​
Tems11 [23]

Explanation:

<em>Hi</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em>

<em>Energy</em><em> </em><em>is</em><em> </em><em>defined</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>capacity</em><em> </em><em>or</em><em> </em><em>ability</em><em> </em><em>to</em><em> </em><em>do</em><em> </em><em>work</em><em>.</em><em> </em><em>It's</em><em> </em><em>SI</em><em> </em><em>unit</em><em> </em><em>is</em><em> </em><em>Joule</em><em>.</em>

<em>here</em><em>,</em>

<em>Joule</em><em> </em><em>=</em><em> </em><em>(</em><em>kg</em><em>×</em><em>m</em><em>×</em><em>m</em><em>)</em><em>/</em><em>(</em><em>s</em><em>×</em><em>s</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>kg</em><em>×</em><em>m</em><em>^</em><em>2</em><em>/</em><em>s</em><em>^</em><em>2</em><em>.</em>

<em>Therefore</em><em>, </em><em> </em><em>the</em><em> </em><em>derived</em><em> </em><em>unit</em><em> </em><em>is</em><em> </em><em>kg</em><em>.</em><em>m</em><em>^</em><em>2</em><em> </em><em>by</em><em> </em><em>s</em><em>^</em><em>2</em><em>.</em>

<em>Hope it helps</em><em>.</em><em>.</em><em>.</em>

7 0
3 years ago
When a pendulum is at the position all the way to the left when it is swinging (at the top of the arc), what is true of the kine
JulsSmile [24]
Choice - B is the correct one.

At the top of the arc, at one end of the swing:
-- it's not going to get any higher, so the potential energy is maximum
-- it stops moving for an instant, so the kinetic energy is zero

At the bottom of the arc, in the center of the swing:
-- it's not going to get any lower, so the potential energy is minimum
-- it's not going to move any faster, so the kinetic energy is maximum
7 0
3 years ago
Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 2.70 m/s. Her husband Bruce suddenly realiz
Katen [24]

Answer:

The velocity is v  =  6.66 \  m/s

Henrietta is at distance s=  18.17 \  m from the under the window

Explanation:

From the question we are told that

The speed of Henrietta is v=  2.70 \ m/s

The height of the window from the ground is h  =  36.5 \  m

Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is

t  =  \sqrt{\frac{2 *  h }{g} }

=> t  =  \sqrt{\frac{2 *  36.5 }{9,8} }

=> t  =  2.73 \  s

Generally the time taken for the lunch to reach Henrietta is mathematically represented as

T =  t +  t_1

Here t_1 is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s

Now

T = 2.73  +  4

=> T = 6.73 \  s

Generally the distance covered by Henrietta before catching her lunch is

s=  v  *  T

=> s=  2.70  * 6.73

=> s=  18.17 \  m

Generally the speed with which Bruce threw her lunch is mathematically represented as

v  =  \frac{18.17}{2.73}

v  =  6.66 \  m/s

4 0
3 years ago
An office window has dimensions 3.1 m by 2.1 m. As a result of the passage of a storm, the outside air pressure drops to 0.954 a
Virty [35]

Answer:

Net forces which pushes the window is 30342.78 N.

Explanation:

Given:

Dimension of the office window.

Length of the window = 3.1 m

Width of the window = 2.1 m

Area of the window = (3.1\times 2.1) = 6.51\ m^2

Difference in air pressure = Inside pressure - Outside pressure

                                           = (1.0-0.954) atm = 0.046 atm

Conversion of the pressure in its SI unit.

⇒  1 atm = 101325 Pa

⇒ 0.046 atm = 0.046\times 101325 =4660.95 Pa

We have to find the net force.

We know,

⇒ Pressure = Force/Area

⇒ Pressure=\frac{Force }{Area}

⇒ Force =Pressure\times Area

⇒ Plugging the values.

⇒ Force =4660.95\times 6.51

⇒ Force=30342.78 Newton (N)

So,

The net forces which pushes the window is 30342.78 N.

3 0
3 years ago
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