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Ronch [10]
4 years ago
12

Zeros are always considered significant digits when they are to the left of the decimal point

Physics
1 answer:
maksim [4K]4 years ago
7 0

Answer:

Zeros to the left of a decimal can be insignificant place holders, such as in 0.043 (two significant figures).

They can be significant if they are between two digits who themselves are significant, such as in 101.000 (three significant figures).

In the case of a number like 1,000 we can see there is only one significant figure. The zero digits are not between sigfigs.

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It will be easier to lift a load in wheel Barrow if the load is moved towards the wheel. Give reason ​
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yes,  majority of the weight will be supported by the front wheel and not by you.

Explanation:

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Energy waves moving through the air
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Electromagnetic radiation waves:
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What happens to the boiling point of water as you climb higher up a mountain?
Maksim231197 [3]
The higher the pressure, the higher boiling point of water. At lower the pressure, the boiling point of water comes down. So, the lower pressure inreases the boiling resulting more evaporation. As we go higher in altitude, the atmospheric pressure decreases. This results in decreasing the boiling point at higher altitude and increase in boiling of water. In fact, at the sea level ,the the sea water boils at 100 degree C where atmospheric pressre is normal. However , the boiling takes place at a lower temperature at the top of a mountain due to low pressure. In other words the boling is faster at the top of a mountain than that at its foot.
4 0
4 years ago
A car turns into a driveway that slopes upward at a 9 degree angle, car is moving at 6.5 m/s. If the driver lets the car coast,
expeople1 [14]

To put it in the simplest form, the automatic transmission has a torque converter that uses the transmission fluid to turn the other side of the torque converter. Ex. Putting two room fans facing each other and turning one on and wind flowing from one fan makes the second fan facing the rotating fan turn and the idling engine probably doesn't have enough power to hold it.

I guess more technically, in an automatic, the car selects a neutral gear (no gear) when it is at rest, and the brake pedal is pressed. Upon releasing the brake, the car will apply a small forward force that will hold the car steady on a very small gradient or propel it forwards slowly on a flat or downhill gradient. This force is only started when the brake is being released, as this is the indicator for the car to change into 1st gear.

In a situation where a car is rolling back down the hill it is facing up, there could be one or more of several situations at hand.

Most likely, it simply lacks power to hold on the gradient of the slope. In this case, you'll have to perform a hill start to maintain brake force until forward propulsion is enough to move the car forward. Hill starts are almost always necessary for manual transmission cars. Additionally, it could be the driver's pedal transfer from brake to accelerator is to slow. That would also account for some part of the slip.

Okay, what's missing here is the clutch. The clutch as I'm sure you're aware is a series of plates that connect to each other and transfer power due to friction. The amount of friction is adjustable depending on how much force is applied to hold the plates together (or apart). It is easier to see this in a manual car at low speeds, where the driver hovers the clutch actuation pedal around the "Friction Point". This point is the fine line between moving (increased friction between clutch plates holds them together more firmly, thus transferring more power) and staying stationary (clutch plates disengaged from each other). From the Friction Point, any further release of the clutch will cause the car to move forwards because the transmission is engaging with more of the engine's power. Depressing the clutch pedal back in will not have any effect, as it will just keep the clutch plates separate.

In an automatic car, this is all controlled by computer algorithms, determining how much the clutch should be engaged to reach a certain speed. Taking off from the lights on a hill for example will not necessarily register as any different to taking off on flat ground. The effect of this is that the car is assuming that is requires a certain number of revs and a predetermined clutch setting to accelerate smoothly. Due to the increased force the hill provides, the car will move backwards until the power again reaches a level that will overcome its slippage.

One other thing, is that clutches work both ways. Since only friction holds them together, the torque exerted by the wheels back through the drive-train to the clutch can cause the plates to slip when they are not completely engaged. This results in the wheels moving independently of the running engine, as the clutch is separating the forces they would exert on each other.

I think the key thing to note is that despite not having a pedal to operate it, Automatic cars still have a clutch - just one that relies on a computer to function.

If it's not the engine or the clutch which are both behaving as normal, and we're still assuming it's an auto, there could be a problem with the car's computer system, transmission, clutch or gearbox that is causing the slippage. I would assume this is less likely, but it might be worth checking if it happens to your car. your frickin' welcome

6 0
3 years ago
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1) A tiger leaps horizontally from a 7.5 m high rock with a speed of 4.5 m/s. How far from
Artyom0805 [142]

The distance of tiger's leap from the base of rock is 5.58 m

It is a question of two dimensional motion

The time of motion in two dimensional motion is given by:

t= \sqrt{2y/g}

where y is the height and g is  the acceleration due to gravity

y is given to be 7.5m and let us assume g to be 9.8 m/s^2

t = \sqrt{2 * 7.5/9.8}

 = 1.24s

Using time and speed,

We know that distance is the product of speed and time,

Distance= speed x time

speed is given to be 4.5 m/s

distance from the base of rock = 4.5 x 1.24

                                                    = 5.58m

Hence the distance of tiger's leap from the base of rock is 5.58 m

Disclaimer:

The acceleration due to gravity is assumed to be 9.8 m/s^2

For further reference:

brainly.com/question/11213880?referrer=searchResults

#SPJ9

8 0
1 year ago
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