Answer:
<u><em>First Reaction:</em></u>
=> 
<u><em>Second Reaction:</em></u>
=> 
<u><em>Combined Reaction:</em></u>
=> 
Answer:
E = k λ₀ / x₀, the field is in thenegative direction of the x axis (-x)
Explanation:
In this problem the electric field of a line of charge is requested, the expression for the electric field is
E = k ∫ dq / r²
where k is the Coulomb constant that you are worth 9 10⁹ N m²/C², that the charge and r the distance to the point of interest, in this case it is the origin (x = 0)
let's use the definite linear density
λ₀ = dq / dx
dq = λ₀ dx
we replace and integrate
E = k λ₀ ∫ dx / x²
E = k λ₀ ( -1 / x)
we evaluate the integral from the lower limit of load x = x₀ to the upper limit x = ∞
E = - k λ₀ (1 /∞ - 1 / x₀)
E = k λ₀ / x₀
as the field is positive the direction is away from the charges, so it is in the negative direction of the x axis (-x)
Answer:
1. acceleration value
2. 20 m
3a. when you throwing somethinb upward
3b. when a thing reach maximum height after throwing upward
4. (entire only) velocity = diaplacement/ time = 0/91 = 0
speed = distance/time = 200/91 = 2.2 m/s
5. (40-20)/4 = 5 m/s²
6. displacement using phytagoras get 50 m
velocity = displacement/time = 50/(6+4) = 5 m/s
7. 0, it turn back to the base
8. speed = distance/time = (240*2)/(4+6) = 48 km/h
9. s = (4+14)*3/2 =27 m
Explanation:
the skydiver will be pulled back when parachute is opened they will be moving at a constant speed..
There are no correct choices on the list you provided. Any unit of acceleration is (a unit of length) divided by (a unit of time, squared).