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Maurinko [17]
3 years ago
11

Book sliding across a frictionless table would never stop moving, even though there is

Physics
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

Yes, this is true, unless there were other outside forces, such as wind.

Explanation:

The First Law of Motion states, "A body at rest will remain at rest, and <u>a body in motion will remain in motion unless it is acted upon by an external force."</u>

<u />

<em>Hope this helped!!  :)</em>

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What is the acceleration, in meters per second squared, of a 2,000,000-kilogram NASA rocket with an applied force of 20,000,000
liubo4ka [24]

Answer:

10m/s^2

Explanation:

Force = mass x acceleration

Acceleration = force/ mass

= 20000000/2000000

=10m/s^2

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2 years ago
Which of the following will attract one another? A. The north pole of magnet and the south pole of another magnet B. The north p
Elena L [17]
A. is the correct answer
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3 years ago
A taxi starts from Monument Circle and travels 5 kilometers to the east for 5 minutes. Then it travels 10 kilometers to the sout
katovenus [111]

The correct sentence is:

The taxi is moving with reference to  A) Monument circle. For each leg of the trip, the taxi’s  A) Average speed stays the same, but its  B) Average velocity  changes.

In fact, speed it is only the ratio between the distance traveled and the time taken - so it does not take into account the direction of motion. The speed in the first leg is

v=\frac{5 km}{5 min}=1 km/min

while the speed in the second leg is

v=\frac{10 km}{10 min}=1 km/min

so the speed stays the same.

However, the velocity also takes into account the direction of motion: in the first leg, the direction is east, while in the second leg, the direction is south, therefore the average velocity has changed, since the direction has changed.

4 0
2 years ago
Read 2 more answers
A force that needs to touch something to affect it
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8 0
3 years ago
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66. Calculate the displacement and velocity at times of (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, and (d) 2.00 s for a ball thrown st
kozerog [31]

Answer:

a) t=1s

y = 10.1m

v=5.2m/s

b) t=1.5s

y =11.475 m

v=0.3m/s

c) t=2s

y =10.4 m

v=-4.6m/s  (The minus sign (-) indicates that the ball is already going down)

Explanation:

Conceptual analysis

We apply the free fall formula for position (y) and speed (v) at any time (t).

As gravity opposes movement the sign in the equations is negative.:  

y = vi*t - ½ g*t2 Equation 1

v=vit-g*t  Equation 2

y: The vertical distance the ball moves at time t  

vi: Initial speed

g= acceleration due to gravity

v= Speed the ball moves at time t  

Known information

We know the following data:

Vi=15 m / s

g =9.8 \frac{m}{s^{2} }

t=1s ,1.5s,2s

Development of problem

We replace t in the equations (1) and (2)  

a) t=1s

y = 15*1 - ½ 9.8*1^{2}=15-4.9=10.1m

v=15-9.8*1 =15-9.8 =5.2m/s

b) t=1.5s

y = 15*1.5 - ½ 9.8*1.5^{2}=22.5-11.025=11.475 m

v=15-9.8*1.5 =15-14.7=0.3m/s

c) t=2s

y = 15*2 - ½ 9.8*2^{2}= 30-19.6=10.4 m

v=15-9.8*2 =15-19.6=-4.6m/s  (The minus sign (-) indicates that the ball is already going down)

3 0
3 years ago
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