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san4es73 [151]
4 years ago
12

Good day can I get some help please?​

Physics
1 answer:
abruzzese [7]4 years ago
8 0

Answer:

432 J

Explanation:

When moving linearly:

Kinetic Energy = (1/2)mV^2

So here you have:

KE=(1/2)(6)(12^2)=(1/2)(6)(144)=432

The unit for energy is Joules (J), so your answer would be 432 J.

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Glycerin at a temperature of 30 degrees celcius flows at a rate of 8×10−6m3/sthrougha horizontal tube with a 30mmdiameter. what
marusya05 [52]

The pressure drop in pascal is 3.824*10^4 Pascals.

To find the answer, we need to know about the Poiseuille's formula.

<h3>How to find the pressure drop in pascal?</h3>
  • We have the Poiseuille's formula,

                     Q=\frac{\pi r^4P}{8\beta l}

  • where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.
  • By substituting values and rearranging we will get the pressure drop as,

                  P=3.284Pascals

Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4.

Learn more about the Poiseuille's formula here:

brainly.com/question/13180459

#SPJ4

3 0
1 year ago
How long does it for a car to cover 100 miles at 60 mi/hr? Use one of the following equations:
Mazyrski [523]
1 hour and 40 minutes
4 0
3 years ago
Read 2 more answers
A car accelerates from rest to a velocity of 5 meters/second in 4 seconds. What is its average acceleration over this period of
disa [49]

The average acceleration is

\bar a=\dfrac{5\,\frac{\mathrm m}{\mathrm s}-0\,\frac{\mathrm m}{\mathrm s}}{4\,\mathrm s}=1.25\,\dfrac{\mathrm m}{\mathrm s^2}

5 0
3 years ago
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Which best describes the law of conservation of mass?
Sergio039 [100]

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

7 0
3 years ago
Is it possible for the momentum of a system consisting of two carts on a low-friction track to be zero even if both carts are mo
choli [55]

Answer:

Yes, if the two carts are moving into opposite directions

Explanation:

The total momentum of the system of two carts is given by:

p=m_1 v_1 + m_2 v_2

where

m1, m2 are the masses of the two carts

v1, v2 are the velocities of the two carts

Let's remind that v (the velocity) is a vector, so its sign depends on the direction in which the cart is moving.

We want to know if it is possible that the total momentum of the system can be zero, so it must be:

p=0\\m_1 v_1 + m_2 v_2 = 0\\m_1 v_1 = -m_2 v_2

From this equation, we see that this condition can only occur if v1 and v2 have opposite signs. Opposite signs mean opposite directions: therefore, the total momentum can be zero if the two carts are moving into opposite directions.

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