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stepladder [879]
3 years ago
5

What is matter in regards to energy?​

Physics
1 answer:
svp [43]3 years ago
8 0

Answer:

Energy always involves. motion in some form. Matter is an object that that up space so it is. measured in units of space

Explanation:

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Two satellites revolve around the Earth. Satellite A has mass m and has an orbit of radius r. Satellite B has mass 6m and an orb
melomori [17]

Answer:

aaaaa

Explanation:

M = Mass of the Earth

m = Mass of satellite

r = Radius of satellite

G = Gravitational constant

F=G\frac{Mm}{r^2}

F=G\frac{M6m}{r_b^2}

G\frac{Mm}{r^2}=G\frac{M6m}{r_b^2}\\\Rightarrow \frac{1}{r^2}=\frac{6}{r_b^2}\\\Rightarrow \frac{r_b^2}{r^2}=6\\\Rightarrow \frac{r_b}{r}=\sqrt{6}\\\Rightarrow r_b=2.44948r

r_b=2.44948r

8 0
4 years ago
The heat energy released or absorbed by a chemical reaction is generally determined by the difference between the energy that
Ket [755]

Answer:

Must be put in to break the bonds in the reactants and the energy that is released upon making the bonds in the products.

Explanation:

The heat energy is absorbed to break the chemical bonds, which are responsible for the attractive interactions between atoms and molecules, and which gives stability to chemical compounds. While the heat energy is released upon making the bonds in the chemical compounds.

5 0
3 years ago
If the block is subjected to the force of F = 500 N, determine its velocity at s = 0.5 m. When s = 0, the block is at rest and t
STatiana [176]

Answer:

The velocity is  4.6 m/s^2

Explanation:

Given:

Force = 500N

Distance  s= 0

To find :

Its velocity at s = 0.5 m

Solution:

\sum F_{x}=m a

F\left(\frac{4}{5}\right)-F_{S}=13 a

500\left(\frac{4}{5}\right)-\left(k_{s}\right)=13 a

400-(500 s)=13 a

a = \frac{400 -(500s)}{13}

a = (30.77 -38.46s) m/s^2

Using the relation,

a=\frac{d v}{d t}=\frac{d v}{d s} \times \frac{d s}{d t}

a=v \frac{d v}{d s}

v d v=a d s

Now integrating on both sides

\int_{0}^{v} v d v=\int_{0}^{0.5} a d s

\int_{0}^{v} v d v=\int_{0}^{0.5}(30.77-38.46 s) d s

\left[\frac{v^{2}}{2}\right]_{0}^{2}=\left[\left(30.77 s-19.23 s^{2}\right)\right]_{0}^{0.5}

\left[\frac{v^{2}}{2}\right]=\left[\left(30.77(0.5)-19.23(0.5)^{2}\right)\right]

\left[\frac{v^{2}}{2}\right]=[15.385-4.807]

\left[\frac{v^{2}}{2}\right]=10.578

v^{2}=10.578 \times 2

v^{2}=21.15

v = \sqrt{21.15}

v = 4.6 m/s^2

8 0
3 years ago
Which effects result from the influence of media and technology on children
Salsk061 [2.6K]
Can cause children into getting cyber bullying, being a thief, sexual behavior, anxiety, and depression
6 0
4 years ago
the maximum normal force a pilot can withstand is about eight times his weight. What is the maximum radius of curvature that a j
neonofarm [45]

Complete Question

the maximum force a pilot can stand is about seven times his weight. what is the minimum radius of curvature that a jet plane's pilot, pulling out of a vertical dive, can tolerate at a speed of 250m/s?

Answer:

The value is    r = \frac{250^2 }{6 * 9.8 }

Explanation:

From the question we are told that

 The  weight of the pilot is   W =  mg

 The maximum force a pilot can withstand is  F_{max} =  7 W =  7 (mg)

 The speed is  v  =  250 \ m/s  

Generally the centripetal force acting on the pilot is equal to the net force acting on the pilot i.e

      F_c =  F_{max} - mg

Here N  is the normal force acting on the pilot

Now

      F_c =  \frac{m v^2 }{r}

So

      \frac{m v^2 }{r} =  7(mg)  - mg  

=>  r = \frac{v^2 }{6g}

=>  r = \frac{250^2 }{6 * 9.8 }

=>  r =  1063 \  m

5 0
3 years ago
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