Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula
where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,
or, 
or, 
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change = 
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
<span> m + n^2
= 2 + (-2)^2
= 2 + 4
= 6
answer is 6</span>
Answer:
Option B is the right choice.
Step-by-step explanation:
Given:
An are CE and an inscribed angle CBE.
Measure of inscribed angle CBE = 25 °
We have to find the measure of the arc CE.
Concept:
- An inscribed angle is an angle with its vertex on the circle.
- The measure of an inscribed angle is half the measure the intercepted arc.
- Measure of inscribed angle = 1/2 × measure of intercepted arc
.
To find the measure of arc CE.
⇒ 
⇒ 
⇒ 
⇒ 
Measure of intercepted arc CE = 50 degrees.
The measure of arc CE = 50° so, option B is the right choice.
Answer:
1024
Step-by-step explanation:
You could put 4^5 into your calculator. It’s 4*4*4*4*4= 1024
4x = student tickets, 7x = adult tickets
4(120) + 7x = 1500
480 + 7x = 1500
7x = 1020
X = 145 adult tickets
