14 is true because all even numbers are multiples of two.
Answer:
<h2><u>E</u><u>k</u>sponent</h2>
![\sf{ \large{ \boxed{ \red{ {a}^{ \frac{n}{m} } = \sqrt[m]{ {a}^{n} } } } }}](https://tex.z-dn.net/?f=%20%20%5Csf%7B%20%5Clarge%7B%20%5Cboxed%7B%20%5Cred%7B%20%7Ba%7D%5E%7B%20%5Cfrac%7Bn%7D%7Bm%7D%20%20%7D%20%20%3D%20%20%5Csqrt%5Bm%5D%7B%20%7Ba%7D%5E%7Bn%7D%20%7D%20%7D%20%7D%20%7D%7D)

![= \sqrt[3]{ {2}^{4} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%5B3%5D%7B%20%7B2%7D%5E%7B4%7D%20%7D%20)
![= \sqrt[3]{2 \times 2 \times 2 \times 2}](https://tex.z-dn.net/?f=%20%3D%20%20%20%5Csqrt%5B3%5D%7B2%20%5Ctimes%202%20%5Ctimes%202%20%5Ctimes%202%7D%20)
![= \boxed {\bold{\sqrt[3]{16}(c.) }}](https://tex.z-dn.net/?f=%20%3D%20%20%20%5Cboxed%20%20%7B%5Cbold%7B%5Csqrt%5B3%5D%7B16%7D%28c.%29%20%7D%7D)
Answer:
2
Step-by-step explanation:
Thats your answerrrrrr
Answer:
The correct option is 1.
Step-by-step explanation:
Given information: The coordinates of a right angled triangle ABC are A(0, 0), B(0, 4a – 5) and C(2a + 1, 2a + 6). Angle ABC = 90°.
It means AB and BC are legs of the right angled triangle ABC.
Side AB lies on the y-axis because the x-coordinate of both A and B is 0.
Two legs are perpendicular to each other. So, BC must be parallel to x-axis and the y-coordinate of both B and C is must be same.



Divide both sides by 2.

The value of a is 2. So the coordinates of triangle ABC are


The area of a triangle is

The area of triangle ABC is





The area of triangle ABC is 102. Therefore the correct option is 1.
<span>4. Simplify the expression.
sine of x to the second power minus one divided by cosine of negative x</span>
<span>(1−sin2(x))/(sin(x)−csc(x))<span>
</span>sin2x+cos2x=1</span>
<span>1−sin2x=cos2x<span>
</span>cos2(x)/(sin(x)−csc(x))</span>
<span>csc(x)=1/sin(x)</span>
<span>cos2(x)/(sin(x)− 1/sin(x))= cos2(x)/((sin2(x)− 1)/sin(x))</span>
<span>sin2(x)− 1=-cos2(x)</span>
<span>cos2(x)/(( -cos2(x))/sin(x))
=-sin(x)</span>
<span>
the answer is the letter a)
-sin x
</span><span>
5. Find all solutions in the interval [0, 2π). (6 points)sin2x + sin x = 0</span> using a graphical tool
the solutions
x1=0
x2=pi
<span>x3=3pi/2
the answer is the letter </span><span>
D) x = 0, π, three pi divided by two</span>