First of all: Note that this is a linear relationship. If you start at any x and increase x by 2, by how much does y decrease? Verify that this decrease is the same for any two adjacent x-values. Can you figure out the slope of this straight line by doing that? Now think about the y-value you'd get if you were to decrease x not by 2, but by 1.
The function can be solved as follows:
- f(6 + 4) = 25
- f(6) - f(4) = 20
- f(6 - 4) = 1
- f(6) - f(4) = 6
- f(6) . f(4) = 91
<h3>How to solve function?</h3>
f(x) = 3x - 5
Therefore, the function can be solved as follows:
f(6 + 4) = f(10) = 3(10) - 5 = 25
f(6) + f(4) = 3(6) - 5 + (3(4) - 5)
f(6) - f(4) = 13 + 7
f(6) - f(4) = 20
f(6 - 4) = f(2) = 3(2) - 5 = 6 - 5 = 1
f(6) - f(4) = 3(6) - 5 - (3(4) - 5)
f(6) - f(4) = 18 - 5 - (12 - 5)
f(6) - f(4) = 13 - 7
f(6) - f(4) = 6
f(6.4) = f(24) = 3(24) - 5 = 72 - 5 = 67
f(6) . f(4) = (3(6) - 5 ) (3(4) - 5)
f(6) . f(4) = (18 - 5)(12 - 5)
f(6) . f(4) = (13)(7) = 91
learn more on function here: brainly.com/question/9390144
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See the attached image for the drawings of the problems. The figures are not to scale. The decimal values in each figure are approximate to one decimal place.
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Focus on Figure 1
sin(angle) = opposite/hypotenuse
sin(A) = BC/AC
sin(36) = 13.2/x
x*sin(36) = 13.2
x = 13.2/sin(36)
x = 13.2/0.58778525229248 <<-- make sure calc is in degree mode
x = 22.4571813404936
x = 22.5
This value is approximate (rounded to one decimal place)
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Move onto Figure 2
cos(angle) = adjacent/hypotenuse
cos(D) = DE/FD
cos(50) = y/57.4
57.4*cos(50) = y
y = 57.4*cos(50)
y = 57.4*0.64278760968653
y = 36.8960087960069
y = 36.9
This value is approximate (rounded to one decimal place)
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Finally, move onto Figure 3
tan(angle) = opposite/adjacent
tan(G) = JH/GH
tan(18) = z/10
10*tan(18) = z
z = 10*tan(18)
z = 10*0.3249196962329
z = 3.249196962329
z = 3.2
This value is approximate (rounded to one decimal place)
24 x 10^4, the 4 comes from with how many jumps it took to land on a whole number from 240,000.
I hold this is hepe I think the answer is C