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konstantin123 [22]
3 years ago
9

A professor wants to award prizes for 1st, 2nd, 3rd, 4th and 5th in the class of 30. In how many ways can the prizes be awarded

(assume no two students tie)
Mathematics
1 answer:
aniked [119]3 years ago
8 0

Answer:

Selection =  17100720\ ways

Step-by-step explanation:

Given

Students = 30

Positions = 5 i.e. first to fifth

Required

Determine number of selection

1st position = Any of the 30 students

2nd position = Any of the 29 students

3rd position = Any of the 28 students

4th position = Any of the 27 students

5th position = Any of the 26 students

Number of selection is then calculated as:

Selection =  30 * 29 * 28 * 27 * 26

Selection =  17100720\ ways

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How do I get the answer??
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Answer:

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Step-by-step explanation:

Hello!

Let's first simplify the radical.

We can do this by expanding the radical:

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