A professor wants to award prizes for 1st, 2nd, 3rd, 4th and 5th in the class of 30. In how many ways can the prizes be awarded
1 answer:
Answer:
Step-by-step explanation:
Given
i.e. first to fifth
Required
Determine number of selection
1st position = Any of the 30 students
2nd position = Any of the 29 students
3rd position = Any of the 28 students
4th position = Any of the 27 students
5th position = Any of the 26 students
Number of selection is then calculated as:
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Answer:
(a)
(b)
(i)probability that the product of the two numbers is a prime number=7/64
(ii)probability that the product of the two numbers is not a perfect square=56/64
(iii)probability that the product of the two numbers is a multiple of 5 =15/64
(iv)probability that the product of the two numbers is Less than or equal to 21 =40/64
(v) probability that the product of the two numbers is divisible by 4 or 6 =42/64
Step-by-step explanation:
(a) 8-sided fair die implies each die can have outcomes 1,2,3,4,5.6,7,8 with equal chances.
To draw the possibility diagram of the product of the two numbers appearing on the die in each throw, we put the outcomes of both dies side by side and find the product of possible outcomes.
(b) probability= Number of outcome / Total number of outcomes
(i)probability that the product of the two numbers is a prime number=8/64=1/8
based on sample space, the prime numbers are 2,2,3,3,5,5,7,7
(ii)probability that the product of the two numbers is not a perfect square=56/64=7/8
based on sample space, only 1,4,9,16,25,36,49,64 are perfect square
(iii)probability that the product of the two numbers is a multiple of 5 =15/64
(iv)probability that the product of the two numbers is Less than or equal to 21 =40/64=5/8
(v) probability that the product of the two numbers is divisible by 4 or 6 =42/64=21/32