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balu736 [363]
4 years ago
10

Solve for x

Mathematics
1 answer:
serg [7]4 years ago
6 0

Hey there!

  • \bold{4x^2+23x+28=0}
  • <em>Firstly,  factor the left side of your equation </em>
  • \bold{(4x+7)(x+4)=0}
  • <em>Set each of your terms to the number of \bold{0}</em>
  • \bold{4x+7=0}  \bold{or}  \bold{x+4=0}
  • \boxed{\boxed{\bold{Answer:D.)x=\frac{-7}{4} [or]x=-4}}} \bold{\checkmark}

Good luck on your assignment and enjoy your day!

~\bold{LoveYourselfFirst:)}

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The math club is electing new officers. There are 5 candidates for president, 6 candidates for vice-president, 2 candidates for
Andre45 [30]

Answer:

180 different combinations

Step-by-step explanation:

To find the number of different combinations possible, We first find the number of possibilities for each place, and then multiply all possibilities.

Number of possibilities for president: 5

Number of possibilities for vice-president: 6

Number of possibilities for secretary: 2

Number of possibilities for treasurer: 3

Number of different combinations: 5*6*2*3 = 180

(We can form 180 different groups of 1 president, 1 vice-president, 1 secretary and 1 treasurer)

8 0
4 years ago
Read 2 more answers
Find the<br> 3 m<br> Diameter=<br> Circumference =<br> Area =
andrezito [222]

Answer:

Answers below

Step-by-step explanation:

Radius = 3m

Diameter:

d = 2r

d = 2(3m)

d = 6m

Circumference:

c = 2πr

c = 2π(3m)

c = 6π m

c = 18.85 m

Area:

A = 2πr^2

A = 2π(3m)^2

A = 18π m^2

A = 56.55 m^2

Please mark brainliest if this helped

Please mark brainliest if this helped

5 0
3 years ago
Mr. Bond’s class wanted to estimate the mean mass of Snickers Fun Size bars. They randomly selected 74 bars and recorded the mas
AleksAgata [21]

Step 1: Find the standard error (SE)

The standard error is given by

SE=\frac{s}{\sqrt[]{n}}\begin{gathered} \text{ Where } \\ SE=\text{ the standard error} \\ s=\text{ the sample standard deviation} \\ n=\text{ the sample size} \end{gathered}

In this case,

n=74,s=0.76

Therefore,

SE=\frac{0.76}{\sqrt[]{74}}\approx0.0883

Step 2: Find the alpha level (α)

\alpha=1-\frac{(\text{Confidence level})}{100}\alpha=1-0.99=0.01

Step 3: Find the critical probability (P*)

P^{\prime}=1-\frac{\alpha}{2}

Therefore,

P^{\cdot}=1-\frac{0.01}{2}=0.995

Step 4: Find the critical value (CV)

The critical value the z-score having a cumulative probability equal to the critical probability (P*).

Using the cumulative z-score table we will find the z-score with value of 0.995

Hence,

CV=2.576

Step 5: Find the margin of error (ME)

ME=SE\times CV

Therefore,

ME=0.0883\times2.576=0.2275

Step 6: Find the confidence interval (CI)

\begin{gathered} CI\text{ is given by} \\ CI=(\bar{x}-ME,\bar{x}+ME) \\ \text{ In this case} \\ \bar{x}=17.1 \end{gathered}

Therefore,

CI=(17.1-0.2275,17.1+0.2275)=(16.8725,17.3275)

Hence there is a 99% probability that the true mean will lie in the confidence interval

(16.8725, 17.3275)

4 0
1 year ago
Write the equation of a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2(sqrt5)
Xelga [282]

Answer:

\frac{x^2}{16}-\frac{b^2}{4}=1

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that  a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{4^2}{a^2}-\frac{0}{b^2} =1\\\frac{4^2}{a^2}=1\\ a^2=16\\a=\sqrt{16}=4\\ a=4

The foci c is at +/-2√5, using c² = a² + b²:

c^2=a^2+b^2\\(2\sqrt{5} )^2=4^2+b^2\\20 = 16 + b^2\\b^2=20-16\\b^2=4\\b=\sqrt{4}=2\\ b=2

Substituting the value of a and b to get the equation of the hyperbola:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\\\frac{x^2}{16}-\frac{b^2}{4}=1

5 0
3 years ago
What is dh/dx if h(x) = cπ, where c is a constant? Please show work. Will mark the best answer as brainliest.
Svetllana [295]

Answer:

h'(x)=0

Step-by-step explanation:

By definition, the derivative of f(x) is given by:

\displaystyle \frac{dy}{dx}=f'(x)=\lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}

Given h(x)=c\pi, h(x+4) must also be c\pi. Therefore, we have:

\displaystyle h'(x)=\lim_{h\rightarrow 0}\frac{c\pi - c\pi }{h},\\h'(x)=\lim_{h\rightarrow 0}\frac{0}{h}=\boxed{0}

Note that the derivative of a constant is always zero since for f(x)=c, where c is some constant, f(x)=f(x+h) and we obtain c-c in the numerator, yielding a final answer of zero.

4 0
3 years ago
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