Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
I believe the answer is B and E
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Answer:
1a) −24x^4−52x^3+198x^2+126x−325
2a) 14x^2+7x−41
3a) 30x^3+9x^2+32x−7
Step-by-step explanation:
Answer:
11
Step-by-step explanation:
Use corresponding angles.
Angle FBC is 180 - 147 which is 33.
This means x is 180 - 33 - Angle EBA.
EBA is 180 - 4x.
x = 180 - 33 - (180 - 4x)
x = 180 - 33 - 180 + 4x
-3x = 180 - 33 - 180
-3x = -33
3x = 33
x = 11
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