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Alinara [238K]
2 years ago
6

An insurance policy is _____.

Business
2 answers:
Marysya12 [62]2 years ago
6 0
An insurance policy is Teara Jones A.K.A "Lil Boat"
Aneli [31]2 years ago
3 0
A document detailing the terms and conditions of a contact of insurance
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Charles has decided to open a​ lawn-mowing company. To do​ so, he purchases mowing equipment for ​$​, buys gasoline ​($ in gas i
Masja [62]

Answer: $8,600

Explanation:

Implicit cost is also known as the opportunity cost which means that it is the benefit of the next best alternative that was foregone when the current decision was made.

The implicit cost here is therefore:

The $8,000 that Charles could have been making as a lifeguard.

The interest per year he could have been earning on the $5,000 he used to buy mowing equipment.

The depreciation on the mowing equipment because depreciation is not an explicit cost but an implicit one.

= 8,000 + (2% * 5,000) + (10% * 5,000)

= 8,000 + 100 + 500

= $8,600

6 0
3 years ago
Jed is an electrician. Jed and his wife are accrual basis taxpayers and file a joint return. Jed wired a new house for Alison an
poizon [28]

Answer:

b. $3,000

Explanation:

Jed was refused payment of $5000, the court awarded only $2000, rest $3000 is a loss for Jed. He can only deduct $3000 and not full $5000 as $2000 has been realized.

Therefore, The amount of loss may Jed deduct in the current year is $3,000.

3 0
2 years ago
Pressure with Two Liquids, Hg and Water. An open test tube at 293 K is filled at the bottom with 12.1 cm of Hg, and 5.6 cm of wa
Radda [10]

Answer:

1170839.28 dyn/cm^2

16.9816 psia

117.083928 kN/m^2

Explanation:

To calculate the absolute pressure in the bottom of tube we need to sum the atmosferic and gauge pressure.

P_{abs}=P_{atm}+P_G

And the gauge pressure is given by the contributions of columns of water (P_{w}) and mercury(P_{Hg}), we can calculate the contribution of each column as:

P= \rho g h (*)

where \rho is the respective density, g gravity and h is height.

So we have all the data required to use the above equations (P_{atm}, height and density of each column) we only need to be carefully with the units.

For simplicity we can to express all pressure contributions in mmHg ( P_{atm}, P_{w} and P_{Hg}). Note that the units "x" mmHg  means the pressure at the bottom of a column of mercury of "x" mm high. For example, in this case we have a column 12.1 cm of Hg, that is a column of 121 mmHg (passing from cm to mm only requires multiply by 10) pressure exerted by that column is 121 mmHg.

Now pressure of 5.6 cm (56 mm) of water would be 56 mm of water, but it is not the same that mmHg, since the density of water is lower, the pressure exerted by 1 mm of water is lower than the exerted by 1 mm of Hg. The conversion between mmHg and mm of water is given by the relation between the densities.

mmHg=\frac{\rho_w*mmH_2O}{\rho_{Hg}}

mmHg=\frac{0.998*mmH_2O}{13.55}=0.0737 mmH_2O

And pressure of water in mmHg is

0.0737*56=4.1246 mmHg

The absolute pressure is:

P_{abs}=P_{atm}+P_G= 756 + 121 + 4.1246  = 881.1246 mmHg = 88.11246cmHg

To pass to dyn/cm^2 units we need to use the equation (*)

P= \rho g h = 13.55 \frac{g}{cm^3} * 980.665 \frac{cm}{s^2} * 88.11246 cmHg = 1170839.28 \frac{g}{cm s^2} = 1170839.28 \frac{dyn}{cm^2}

Note: We need to use cm Hg for units coherence

Now passing from dyn/cm^2 to kN/m^2 (or kPa) we need to consider that 1 dyn is 10^{-8} kN and 1 cm^2 is 10^{-4} m^2.  

1170839.28 \frac{dyn}{cm^2} * \frac{10^{-8}kN}{1 dyn}*\frac{cm^2}{10^{-4}m^2}=117.083928kN/m^2

Now passing kN/m^2 to psia. We need to consider that 1 psia is 6.89476.

117.083928kN/m^2*\frac{1psia}{6.89476kN/m^2}=16.9816 psia

 

8 0
3 years ago
Zero Corp. is an investment company authorized to issue only common stock. During the last half of the current year, Edwards own
Vinil7 [7]

Answer:

the answer its A) An state where Edwards is the beneficiary

Explanation:

why? zero corp is a investment company where any shareholders who wants to be part of it they could, every investment is personal , it means a exchange where you invest money for shares, and it doesn't  affect your business.

7 0
3 years ago
Suppose that the total revenue received by a company selling basketballs is $600 when the price is set at $15 per basketball and
SVETLANKA909090 [29]
I think the answer is <span>unit-elastic over this price range.  This happens  when a company earns the same revenue even with some slight changes on the prices. It means that slight increase or even decrease in price does not affect the revenue of the company.</span>
6 0
3 years ago
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