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Eddi Din [679]
3 years ago
5

Kevin’s salary is $410.00 per week. He will get paid monthly. How Much will his straight time pay be for one month (4 weeks)? A)

$1,640.00 b) $960.00 C)$640.00 d) $1,280.00
Mathematics
1 answer:
Alexxandr [17]3 years ago
8 0
The answer is A)1,640
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Airida [17]

1 hundredth+3 tenths= 3 hundredths

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2 years ago
Round each fraction to the nearest half and find the estimate.
erastova [34]

Answer: The result is one half (\frac{1}{2})

Step-by-step explanation:

We have the following expression:

\frac{2}{6}+\frac{1}{6}

Since both fractions have the same denominator, we can just add both numerators and keep the denominator:

\frac{2+1}{6}=\frac{3}{6}

Dividing numerator and denominator by 3:

\frac{\frac{3}{3}}{\frac{6}{3}}=\frac{1}{2} This is the result

3 0
3 years ago
broderick had 420 dollars in his checking account he made 6 deposits of 35.50 each.He needs to write 4 checks for 310.75 each.Wh
kotykmax [81]
Q.q i dunno , seems like he doesnt have enough money with the 6 deposites of 35.5 = 213 if you add the deposists to 420+213=633 , and he needs 4 checks of 310 eaach , he could only write 2 checks , so i suppose theirs not enough information to  accumulate a answer 
7 0
3 years ago
Read 2 more answers
8 times the sum of a and b
LenaWriter [7]

Answer:

c

Step-by-step explanation:

i did the quiz

4 0
3 years ago
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The distance of a golf ball from the hole can be represented by the right side of a parabola with vertex (-1,8). The ball reache
ddd [48]

Answer:

Let's suppose that the hole is at y = 0m, where x is the time variable.

we know that:

The vertex is (-1s, 8m).

(i suppose x in seconds and y in meters)

At x = 1s, the ball reaches the hole, so we also have the point:

(1s, 0m).

Remember that the vertex of a quadratic equation y = a*x^2 + b*x + c is at:

x = -b/2a,

then we have:

-1 = -b/2a.

Then we have tree equations:

8m = a*(-1s)^2 + b*-1s + c

0m = a*(1s)^2 + b*1s + c

-1s = -b/2a.

First we should isolate one variable in the third equation, and then replace it in one of the other two:

1s*2a = b.

So we can replace b in the first two equations bi 1s*2a.

8m = a*1s^2 - 1s*2a*1s + c

0m = a*1s^2 + 1s*2a*1s + c

We can simplify both equations and get:

8m = a*( 1s^2 - 2s^2) + c = -a*1s^2 + c.

0m = a*(1s^2 + 2s^2) + c = a*3s^2 + c.

Easily we can isolate c in the second equation and then replace it into the first equation:

c = -a*3s^2

The first equation becomes:

8m = -a*1s^2 - a*3s^2 = -a*4s^2

a = 8m/-4s^2 = -2m/s^2.

Now with a, we can find the values of c and b.

c = -a*3s^2 = -(-2m/s^2)*3s^2 = 6m.

b = 1s*2a = 1s*(-2m/s^2) = -2m/s.

Then the equation is:

y = (-2m/s^2)*t^2 + (-2m/s)*t + 6m

5 0
3 years ago
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