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2 years ago

5

Kevin’s salary is $410.00 per week. He will get paid monthly. How Much will his straight time pay be for one month (4 weeks)? A)

$1,640.00 b) $960.00 C)$640.00 d) $1,280.00

1 answer:

Alexxandr [17]2 years ago

8 0

The answer is A)1,640

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5.3: Solutions on a Number Line

andrew11 [14]

Answer:

idfk

Step-by-step explanation:

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2 years ago

A public opinion poll in Ohio wants to determine whether registered voters in the state approve of a measure to ban smoking in a

LUCKY_DIMON [66]

This is an example of "a stratified sample".

<u>Answer:</u> Option B

<u>Explanation:</u>

A group-based sampling process that can be divided into subpopulations. For statistical studies, testing of each subpopulation separately may be useful if subpopulations within a total population differ, thus understood as "Stratified sampling".

One might, for instance, divide a adults sample into subgroups in terms of age, like 18 to 29, 30 to 39, 40 to 49, 50–59 etc with decided age difference as needed. A stratified sample may be more accurate than an easy sample of the similar size by random. As it offers more accuracy, a stratified sample sometimes involves a smaller sample, saving money.

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3 years ago

In slope intercept form, write the equation for the line that passes through the point (2,3) and the point (7,13).

tatuchka [14]

First, Use the slope equation to find the slope of the line passing thru these two points:

m=rise/run

Here, the rise is 13-3, or 10, and the run is 7-2, or 5. Thus, the slope, m, is 10/5, or 2: m=2.

We want the slope-intercept form, so let's begin with its general form:

y=mx+b. Substitute the slope 2 for m: y=2x+b. Now choose either of the given points. Arbitrarily I am choosing (2,3). Then x=2 and y=3.

Substituting these values into y=2x+b: 3 = 2(2) + b, or b= 3 -4, or b = -1.

Then the equation of this line, in slope-intercept form, is y = 2x - 1.

8 0

2 years ago

Which function , A or B has a greater rate of change ? Be sure to include the values for the rates of change in your answer . Ex

arsen [322]

<h2>Answer:</h2>

A rate of change tells us how one quantity changes in relation to another quantity. In a mathematical language, we can write this as follows:

$Rate \ of \ Change=\frac{Change \ in \ y}{Change \ in \ x}$

For linear functions. the rate of change is the slope of the line. Thus:

FOR THE TABLE:

By taking two points we can get the rate of change, so let's take $(1,5) \ and \ (2,7)$ :

$ROC=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ ROC=\frac{7-5}{2-1} \\ \\ ROC=\frac{2}{1} \\ \\ \boxed{ROC=2}$

FOR THE GRAPH:

Let's take $(1,1) \ and \ (2,4)$ :

$ROC=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ ROC=\frac{4-1}{2-1} \\ \\ ROC=\frac{3}{1} \\ \\ \boxed{ROC=3}$

As you can see, $3>2$ so <em>the ROC of the function given by the graph is greater than the ROC of the function given by the table.</em>

3 0

3 years ago

Explain why S = {(5, 4, -2), (-15, -12, 6), (10, 8, -4)} is NOT a basis for R^3 (1 point Sis linearly dependent and spans R3 S i

earnstyle [38]

$S$ would be a basis for $\mathbb R^3$ if

(1) the vectors in $S$ are independent, and

(2) the vectors span $\mathbb R^3$ .

Linear independence requires that $c_1=c_2=c_3=0$ is the only solution to

$c_1(5,4,-2)+c_2(-15,-12,6)+c_3(10,8,-4)=(0,0,0)$

These vectors are not linearly independent because if $c_1=3$ , $c_2=1$ , and $c_3=0$ , we have

$3(5,4,-2)+(-15,-12,6)=(15-15,12-12,-6+6)=(0,0,0)$

so $S$ is not a basis for $\mathbb R^3$ .

7 0

2 years ago