In ΔEFG, the measure of ∠G=90°, the measure of ∠F=38°, and FG = 6.7 feet. Find the length of EF to the nearest tenth of a foot.
1 answer:
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Answer: OPTION C.
Step-by-step explanation:
1. To solve this problem you must apply the Pythagorean Theorem, which is shown below:
Where a is the hypotenuse, and b and c are the legs of the triangle.
2. When you solve for one of the legs and substitute values, you obtain that the result is:
3 RIGHT TRIANGLES
1 big right triangle is divided into 2 smaller ones. Medium and small.
<span> a.How far is the spot on the beach from the parking lot? </span>Medium triangle: long leg = 32 m ; short leg = x
Small triangle: long leg = x ; short leg = 18m
32/x = x/18
32*18 = x*x
576 = x²
√576 = √x²
24 = x
Parking lot to the beach is 24 meters.
<span>b. How far will he have to walk from the parking lot to get to the refreshment stand?</span>Use Pythagorean theorem:
Medium triangle: long leg = 32 m ; short leg = 24 m ; hypotenuse = ?
32²+ 24² = c²
1024 + 576 = c²
1600 = c²
√1600 = √c²
40 m = c
Parking lot to refreshment stand is 40 meters.
