Hello,
f(x)=2x^3-x^2-4x+9=(((0+2)x-1)x-4)x+9
f(3)=(((0+2)*3-1)*3-4)*3+9=((2*3-1)*3-4)-3+9=(5*3-4)*3+9=11*3+9=33+9=42
or
f(3)=2*3^3-3^2-4*3+9=2*27-9-12+9=54-12=42
Answer:
yes
Step-by-step explanation:
Answer:
seven and sixty-four thousandths
Step-by-step explanation:
in factors it would be
7 x 1
+ 0 x 0.1
+ 6 x 0.01
+ 4 x 0.001
Answer:
sorry i dont know this this is very hatd question necause i cant have studied
