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3 years ago

3/5 of a fence was installed in 1 1/2 days. how many days to install the whole fence?

2 answers:

7 0

First, let's convert the mixed number 1 1/2 to the improper fraction 3/2. We're given that it takes 3/2 days to install 3/5 of a fence. We're looking for how long it takes to install one whole fence - or 5/5 of a fence. To determine that, let's first find out how long it takes to install 1/5 of a fence, and then multiply that quantity by 5 to obtain our answer.

If it takes 3/2 days (3 half-days) to install 3/5 of a fence (3 fifths of a fence), then it makes sense that it would take 1/2 day (1 half-day) to install 1/5 of a fence (1 fifth of a fence).

If it takes 1/2 day to install 1/5 of a fence, then it should take 5 times that amount of time to install all 5/5 of it, or 5 * (1/2) = 5/2 days, or 2 1/2 days as a mixed number.

Crank3 years ago

3 0

It will take 2 1/2 days to install the whole fence

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Find the distance between the points (0,-8) and (3,2). Round your answer to the nearest hundredth.

Reil [10]

Answer:

10.44

Step-by-step explanation:

First plot each of the points on to a graph at their respective positions.

Following that create a 90° triangle out of the points. This will create a 3 by 10 triangle. (3 to 0 is 3) (-8 to 2 is a difference of 10)

You can then use the pythagorean theorem $a^{2} +b^{2} = c^{2}$ .

Insert the lengths of each of the sides that we got earlier which would be 3 and 10 into the equation. $3^{2} + 10^{2} = c^{2}$

Since we want to find the hypotenuse which is equal to c we work the equation to 9+100 = $c^{2}$ which in turn is 109 = $c^{2}$

Then take the square root of 109 to remove the square from the c to get c = 10.44

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3 years ago

a shopkeeper purchased a TV at ₹15,000 and gives a discount of 20% on its marked prize and still got a profit of 8% . find the m

Setler79 [48]

$\huge\sf\underline{Answer}$

$\sf\longrightarrow selling \: prize \: = \frac{100 + profit\%}{100} \times cp$

$\sf\longrightarrow \frac{108}{100} \times 15000 = 16200$

Let the marked prize of the TV be x .

$\sf\longrightarrow discount = 20\% \: of \: x \: = \frac{20}{100}x = \frac{x}{5}$

We have SP = MP - Discount

$\sf\longrightarrow 16200 \: = \: x - \frac{x}{5}$

$\sf\longrightarrow 16200 \: = \frac{4x}{5}$

$\sf\longrightarrow x \: = \: 20250$

Hence , The marked prize of the TV is ₹20,250 .

Hope it helps ~

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2 years ago

If ADEF is reflected over the x-axis, what would be the coordinates of point F?

Brut [27]

Answer:

Please check the explanation.

Step-by-step explanation:

Let the coordinates of the point F be (x, y).

When a point F(x, y) is reflected over the x-axis, the x-coordinate of the point F remains the same, and the y-coordinate of the point reverses the sign.

Thus, the rule of reflection over the x-axis:

F(x, y) → F'(x, -y)

Here,

F'(x, -y) would be coordinates of point F after the reflection over the x-axis.

Let say, the point F(1, 2).

The coordinate of the point F after the reflection over the x-axis would be:

F(1, 2) → F'(1, -2)

Thus, F'(1, -2) would be the coordinates of point F after the reflection over the x-axis.

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3 years ago

Which statements are true about the place values in the number 88.888?

KIM [24]

I believe A and B are the ones. As for explaining? hmm. I would honestly say that any number to the right of a number is a tenth of the place above it. But then again, it's optional to explain ;P

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