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3 years ago

The area of a rectangle is 120m squared the length of the rectangle is 15m what is the width?

Mathematics

1 answer:

jeka57 [31]3 years ago

3 0

Area of a rectangle = width × length
Width of a rectangle = $\frac{Area}{Length}$ 
The width of this rectangle = $\frac{120}{15}$
= 8 cm

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An author published a book which was being sold online. The first month the author sold 21000 books, but the sales were declinin

Wittaler [7]

Answer: 119,616

You may have to erase the comma when inputting the answer.

=======================================================

Explanation:

The author sells 21,000 books in the first month.

Then they sell 21,000*(1-0.12) = 21,000*(0.88) = 18,480 in the second month.

Then they sell 18,480*(1-0.12) = 18,480*(0.88) = 16,262.4 = 16,262 in the third month.

And so on. These values follow a geometric sequence with first term a = 21,000 and common ratio r = 0.88

We can think of the 0.88 as 88% of the original value (since losing 12%, we keep the remaining 88%)

-------------

Use the formula below to sum the first 9 terms of the geometric sequence

Plug in a = 21000 and r = 0.88

$S_n = a*\frac{1-r^n}{1-r}\\\\S_9 = 21000*\frac{1-0.88^9}{1-0.88}\\\\S_9 \approx 21000*\frac{0.6835216}{0.12}\\\\S_9 \approx 21000*5.6960133\\\\S_9 \approx 119,616.2793\\\\S_9 \approx 119,616\\\\$

The author sold about 119,616 books over the course of the first nine months.

4 0

3 years ago

Suppose the names of the months of the year are placed in a hat and a name is drawn at random. (a) list the sample space for thi

ollegr [7]

(a)

The sample space is a set whose elements are all the possible outcomes for the experiment. Since we will extract one of the months of the years, the sample space is the set composed by all the 12 months:

$\Omega = \{ \text{January},\ \text{February},\ldots,\text{December}\}$

(b)

An event is a subset of the sample space. Events are often defined by their properties. In this example, the event E is the subset of the sample space defined as

$E = \{ x \in \Omega: x \text{ starts with the letter J}\}$

So, we have

$E = \{\text{January},\ \text{June},\ \text{July}\}$

(c)

If all outcomes have equal probability, then the probability of an event is the ratio bewteen its cardinality, and the cardinality of the whole sample space:

$P(E) = \dfrac{n(E)}{n(\Omega)} = \dfrac{3}{12} = \dfrac{1}{4}$

In words, since there are three months beginning with J out of 12 months, we have a probability of 3 over 12 to pick a month starting with J, which simplifies to 1 over 4.

3 0

4 years ago

1.Scale Factor : 4

Montano1993 [528]

Answer:

need points sorry

Step-by-step explanation:

5 0

3 years ago

Use the net to determine the total surface area.

Shtirlitz [24]

not sure 340.8 cm2

4 0

3 years ago

Read 2 more answers

Write an equivalent expression for the expression shown below: a/3 + a/3 + a/3

iris [78.8K]

Answer:

3 (a/3) = a

Step-by-step explanation:

a/3 + a/3 + a/3

3 times a/3

the 3's cancel each other out

Keep up the good work! =)

3 0

4 years ago