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3 years ago

Please help! Will give brainliest answer

Mathematics

2 answers:

Snowcat [4.5K]3 years ago

6 0

They are B. supplementary.

Why?

Because consecutive adjacent angles that form a linear pair (a line) are supplementary. They have a total of 180°.

sergiy2304 [10]3 years ago

3 0

You answer is B because supplementary is 180°

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10 divided by <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D" id="TexFormula1" title="\frac{1}{2}" alt="\frac{1}{2}" al

Ilya [14]

10÷1/2

≈10/1÷1/2

KFC

10/1×2/1

=20/1=20

Hope this helped- have a good day, cya)

7 0

2 years ago

Read 2 more answers

A and B are independent events. P(A)=0.80 and P(B)=0.10. what is P(A and B)?

vaieri [72.5K]

You multiply them so it would be 0.08

8 0

3 years ago

Read 2 more answers

Lewis walked 9/10 of a mile. His friend walked 2/5 of the way with him. How many miles did Lewis's friend walk with him?

iVinArrow [24]

Answer:

Lewis's friend walked with him 9/25 miles

Step-by-step explanation:

Given that

Lewis walked 9/10 of a mile

And His friend accompanied him on 2/5 of the way.

This is a simple question of fraction multiplication

The fraction 2/5 has to multiplied with the miles walked by lewis

$= \frac{2}{5} * \frac{9}{10}\\=\frac{9}{25}$

Hence,

Lewis's friend walked with him 9/25 miles

5 0

2 years ago

Whats the answer for this

UNO [17]

Answer:

Sending care packages is a way to:

ARemember relatives who served incorrect answer

BSupport deployed soldiers incorrect answer

CDonate to military charities incorrect answer

DTeach the history of Memorial Day

Step-by-step explanation:

3 0

2 years ago

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

5 0

2 years ago