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julia-pushkina [17]
3 years ago
7

Please help Math (Surface area) ASAP

Mathematics
1 answer:
Alex787 [66]3 years ago
3 0
92.2 is the answer to your question
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Acell divides into 2 cells every min. Calculate the number of cells after 10 min.
Rainbow [258]

Answer:

20

Step-by-step explanation:

2 cells per minute

and ten minutes of it

so ...10 x 2

8 0
2 years ago
Oscar's dog house is shaped like a tent. The slanted sides are both 5 feet long and the bottom of the house is 6 feet across. Wh
mars1129 [50]

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height is 4ft.

Step-by-step explanation:

I used pathagorus theorem .All explaination is in the pic below.

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Describe real life situations that use parallel lines ?????
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3 years ago
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40 POINTS!!!!!!!! NEED HELP
aniked [119]
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6 0
2 years ago
Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}

From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
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