Answer:
a. 2^3
b. 3^4
c. 4^3 × 5^2
d. 9^4 × 7^2
Step-by-step explanation:
The following equations are given
a. 2 × 2× 2
b. 3 × 3 × 3 × 3
c. 4 × 4 × 4 × 5 × 5
d. 9 × 7 × 9 × 9 × 7 × 9
We need to find the index notation for the above equations
a. 2^3
b. 3^4
c. 4^3 × 5^2
d. 9^4 × 7^2
In this way it should be done
The same would be relevant
The correct answer above would be C.
There are 10 letters in the set {a, b, c, d, e, f, g, h, i, j} which is the pool of letters to choose from when making these three letter codes.
We have 10 choices for slot 1
Then 9 choices for slot 2. This is because we can't reuse the choice for slot 1
Then 8 choices for slot 3
Overall, there are 10*9*8 = 90*8 = 720 different permutations
Answer: 720
Note: you can use the nPr permutation formula with n = 10 and r = 3 to get the same answer
Answer:
50
Step-by-step explanation:
The normal vector to the plane <em>x</em> + 3<em>y</em> + <em>z</em> = 5 is <em>n</em> = (1, 3, 1). The line we want is parallel to this normal vector.
Scale this normal vector by any real number <em>t</em> to get the equation of the line through the point (1, 3, 1) and the origin, then translate it by the vector (1, 0, 6) to get the equation of the line we want:
(1, 0, 6) + (1, 3, 1)<em>t</em> = (1 + <em>t</em>, 3<em>t</em>, 6 + <em>t</em>)
This is the vector equation; getting the parametric form is just a matter of delineating
<em>x</em>(<em>t</em>) = 1 + <em>t</em>
<em>y</em>(<em>t</em>) = 3<em>t</em>
<em>z</em>(<em>t</em>) = 6 + <em>t</em>
