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lilavasa [31]
3 years ago
14

In a CBS News survey done in 2009, 95% of n=346 randomly sampled married men said that they would marry their spouse again if th

ey had it to do all over again. In the same survey, 85% of n=522 married women said that they would marry their spouses if they had to do it over again. a. Calculate a 95% confidence interval that estimates the difference in proportions of married women and men who would marry their spouse again if they had it to do all over again. b. On the basis of the confidence interval determined in part a, can we infer that the population proporti
Mathematics
1 answer:
Nitella [24]3 years ago
5 0

Answer:

456

Step-by-step explanation:

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PLSSS HELP!!!! in need of help immediately! (check whole picture) and pls don’t leave a link.
lys-0071 [83]

Answer: C!!!!!!!

Step-by-step explanation:

Decomposers ( however you spell it ) are things that eat and uhh remove the waste and let other decompopers eat they waste

8 0
3 years ago
A line segment has endpoints at (–4, –6) and (–6, 4). Which reflection will produce an image with endpoints at (4, –6) and (6, 4
Natasha2012 [34]
Reflection on the -x axis
7 0
3 years ago
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How to solve this limit?
wlad13 [49]
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2/(1/x^2-1)  as x approaches infinity you have 2/-1=-2

For the second part the exponent approaches zero as x approaches infinity and anything raised to the zero power is equal to 1 so you have:

-2+1=-1

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3 0
3 years ago
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Given that tan 0=-4/7 , and 270 degrees <0<360 degrees , what is the exact value of sec0?
Elanso [62]
I take it you meant θ angle, anyway.

we know the tan(θ) = -4/7... alrite, we also know that 270° < θ < 360°, which is another to say that θ is in the IV quadrant, where the adjacent side or "x" value is positive whilst the opposite side or "y" value is negative.

\bf tan(\theta )=\cfrac{\stackrel{opposite}{-4}}{\stackrel{adjacent}{7}}\impliedby \textit{now let's find the \underline{hypotenuse}}&#10;\\\\\\&#10;\textit{using the pythagorean theorem}&#10;\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{7^2+(-4)^2}\implies \implies c=\sqrt{65}\\\\&#10;-------------------------------\\\\&#10;sec(\theta )=\cfrac{\stackrel{hypotenuse}{\sqrt{65}}}{\stackrel{adjacent}{7}}
6 0
3 years ago
Can you give me the answer please
uranmaximum [27]

[Chorus]

I might just K.O., the Perc' up in my Faygo

Run up on me wrong, turn his head into a bagel

On the opposition block, just like a Lego

I'm big homie, b, so you know that I got say-so

4 0
3 years ago
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