Distances in 2- and 3-dimensions (and even higher dimensions) can be found using the Pythagorean theorem. The straight-line distance can be considered to be the hypotenuse of a right triangle whose sides are the horizontal and vertical differences between the coordinates.
Here, you have A = (0, 0) and B = (3, 6). The horizontal distance between the points is ...
... 3 - 0 = 3 . . . . the difference of x-coordinates
The vertical distance between the points is ...
... 6 - 0 = 6 . . . . the difference of y-coordinates
Then the straight-line distance (d) between the points is found from the Pythagorean theorem, which tells you ...
... d² = 3² + 6²
... d = √(9 + 36) = √45 ≈ 6.7 . . . units
y = mx , where m is a slope,
m= rise/run
We have y = 15x, so m =15 and rise/run =15, then
rise = 15, run = 1
Treat this as if the inequality sign was the same thing as an equal sign. Most of the equality rules apply to inequalities (with a few exceptions)
Subtract both sides by 4
Multiply both sides by 2
We want the unknown variable on the left side (because it looks nicer)
Answer: x = t, y = 2t/3 + 2
Step-by-step explanation:
You want to write both x and y in terms of t
so if you rearrange 4x - 6y = -12 you get
-6y = -4x - 12
6y = 4x + 12
y = 2x/3 + 2
set x = t
and y = 2t/3 + 2
and that's it!
another one you could do is
x = t/2
y = t/3 + 2
or even
x = 3t/2
y = t + 2
i like this one the most because it looks more elegant
Answer:
is it 22.
Step-by-step explanation:
is it?
