If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the
average of x, y, and z in terms of m?
A) m + 6
B) m + 7
C) 2m + 14
D) 3m + 21
2 answers:
Answer:
B) m + 7
Step-by-step explanation:
We know that we have:
(m + 9)/2 = x
(2m + 15)/2 = y
(3m + 18)/2 = z
We need to find the average.
= (x + y + z)/3
= (m+9/2) + (2m+15/2) + (3m+18/2) / 3
= (m + 9) + (2m + 15) + (3m + 18) / 6
= (6m + 42) / 6
= (m + 7)
Best of Luck!
Answer:
Step-by-step explanation:
<h3>Given</h3>
- x = (m + 9)/2
- y = (2m + 15)/2
- z = (3m + 18)/2
<h3>To find</h3>
<h3>Solution</h3>
<u>Average of x, y and z is:</u>
<u>Substituting the values of x, y and z</u>
- ((m + 9)/2 + (2m + 15)/2 + (3m + 18)/2)/3 =
- ((m + 9+ 2m + 15 + 3m + 18)/2)/3 =
- (6m + 42)/6 =
- m + 7
<u>Correct option is</u> B) m + 7
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