What is the mass of this cucumber?

The weights of newborn babies are distributed normally, with a mean of approximately 105 Oz and a standard deviation of 15 Oz. I

ICE Princess25 [194]

Answer:

0.999 = 99.9% probability that the baby weighs less than 150 Oz.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The weights of newborn babies are distributed normally, with a mean of approximately 105 Oz and a standard deviation of 15 Oz.

This means that $\mu = 105, \sigma = 15$

What if the probabability that the baby weighs less than 150 Oz?

This is the pvalue of Z when X = 150. SO

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{150 - 105}{15}$

$Z = 3$

$Z = 3$ has a pvalue of 0.999

0.999 = 99.9% probability that the baby weighs less than 150 Oz.

7 0

2 years ago

A circle is centered at the point (5, -4) and passes through the point (-3, 2).

Sedbober [7]

Answer:

The equation of the circle is (x + -5)² + (y + 4)² = 100

Step-by-step explanation:

* Lets revise the standard form of the equation of the circle

- If the center of the circle is point (h , k) and the length of its radius is r,

then the equation of the circle is (x - h)² + (y - k)² = r² in standard form

* Now lets solve the problem

- The center of the circle is point (5 , -4)

∴ h = 5 and k = -4

∴ The equation of the circle is (x - 5)² + (y - -4)² = r²

∴ The equation of the circle is (x - 5)² + (y + 4)² = r²

- The circle passes through the point (-3 , 2)

- To find r substitute the x-coordinate and the y-coordinate of the

point in the equation of the circle

∵ Point (-3 , 2) is on the circle

∴ x = -3 and y = 2

∴ (-3 - 5)² + (2 + 4)² = r² ⇒ simplify it

∴ (-8)² + (6)² = r² ⇒ solve power 2

∴ 64 + 36 = r² ⇒ add the like terms

∴ 100 = r²

∵ The equation of the circle is (x - 5)² + (y + 4)² = r²

∴ The equation of the circle is (x - 5)² + (y + 4)² = 100

- To complete the form

∴ The equation of the circle is (x + -5)² + (y + 4)² = 100

8 0

3 years ago

Andrew took a random sample of 10 decorated ceramic cups from a population of 100 cups to determine the sample mean number of de

fgiga [73]

He difference between their sample means would likely stay the same.

I hope this help

4 0

3 years ago

Read 2 more answers

Answer the question is it <br> A <br> B <br> C or <br> D

MrRa [10]

i think its c lmk if i am wrong

7 0

3 years ago

Evaluate the surface integral. ??s (x2 y2 z2 ds s is the part of the cylinder x2 y2 = 4 that lies between the planes z = 0 and z

kondor19780726 [428]

The surface $S$ can be parameterized by

$\mathbf r(\theta,z)=(2\cos\theta,2\sin\theta,z)$

where $0\le\theta\le2\pi$ and $0\le z\le2$ . Then the surface integral can be computed with

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS$
$\displaystyle=\int_{\theta=0}^{\theta=2\pi}\int_{z=0}^{z=2}(4\cos^2\theta+4\sin^2\theta+z^2)\|\mathbf r_\theta\times\mathbf r_z\|\,\mathrm dz\,\mathrm d\theta=\dfrac{128\pi}3$

6 0

3 years ago