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SCORPION-xisa [38]

3 years ago

11

I have a value that is 35% of the total value. I want to know what the total value is and what formula is used to work this out?

1 answer:

Serjik [45]3 years ago

8 0

Since 35% is 0.35 ( by moving the decimal point 2 spots to the left) and 100% (the total value) is 1, we want to see how much we want to multiply the value (we'll call it x for now) by to get the total value. To get that, we divide 1 by 0.35 to get 1/0.35. Therefore, the formula is x*1/0.35

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Explain:<br><br><br><br><br><br><br><br><br><br> 10 to the 3rd power

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The output of a function or relation, or the set of y-values that a graph is defined for, is called the ___.

Andre45 [30]

Answer:

Range

Step-by-step explanation:

The range of a graph tells you <u>all of the possible y-values</u> for it.

There is also the domain, which tells you all of the possible x-values.

For example, if you have this relation, that only has these points:

(1, 2) (2, 4) (3, 6)

Then the range is {2, 4, 6}. This means the "y" can ONLY be the numbers stated here.

The domain would be {1, 2, 3}.

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3 years ago

Each egg carton holds one dozen eggs. Michael's chicken farm fills 121 egg cartons. He thinks that there were over 1500 eggs. Is

Kobotan [32]

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3 years ago

Prove the divisibility:<br><br>45^45·15^15 by 75^30

garri49 [273]

Answer:

$3^{75}$ .

Step-by-step explanation:

We have been an division problem: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(9*5)^{45}=9^{45}*5^{45}$

$15^{15}=(3*5)^{15}=3^{15}*5^{15}$

$75^{30}=(15*5)^{30}=15^{30}*5^{30}$

Substituting these values in our division problem we will get,

$\frac{9^{45}*5^{45}*3^{15}*5^{15}}{15^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{9^{45}*5^{(45+15)}*3^{15}}{15^{30}*5^{30}}$

$\frac{9^{45}*5^{60}*3^{15}}{15^{30}*5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{(3*3)^{45}*5^{60}*3^{15}}{(3*5)^{30}*5^{30}}$

$\frac{3^{45}*3^{45}*5^{60}*3^{15}}{3^{30}*5^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{3^{(45+45+15)}*5^{60}}{3^{30}*5^{(30+30)}}$

$\frac{3^{105}*5^{60}}{3^{30}*5^{60}}$

$\frac{3^{105}}{3^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{105}}{3^{30}}=3^{105-30}$

$3^{105-30}=3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

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3 years ago

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lesya692 [45]

Answer:

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Step-by-step explanation:

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