ANSWER
B.Yes, f is continuous on [1, 7] and differentiable on (1, 7).
EXPLANATION
The given
The hypotheses are
1. The function is continuous on [1, 7].
2. The function is differentiable on (1, 7).
3. There is a c, such that:
This implies that;
Since the function is continuous on [1, 7] and differentiable on (1, 7) it satisfies the mean value theorem.
Answer:
Option (3)
Step-by-step explanation:
If binomial (x - 6) and trinomial (-2x² + x + 9) are the factors of a polynomial then their multiplication will be equal to the polynomial.
(x - 6)(-2x² + x + 9) = x(-2x² + x + 9) - 6(-2x² + x + 9)
= -2x³ + x² + 9x + 12x² - 6x - 54
= -2x³ + 13x² + 3x - 54
Therefore, Option (3) will be the correct option.
L = 3x width
2L + 2W = 16 units
2(3W) + 2W = 16 units
8W = 16 units
Width = 2 units
Given:
4 1/7 * 3 3/5
4 1/7 = (4*7)+1/7 = 29/7
3 3/5 = (3*5)+3/5 = 18/5
29/7 * 18/5 = 29 * 18 / 7 * 5 = 522 / 35 = 14.91
Simplified expression.
4 x 3 1/2
3 1/2 = (3*2)+1/2 = 7/2
4 * 7/2 = 4*7 / 2 = 28 / 2 = 14
It is a close estimate. Actual: 14.91 vs Estimate: 14