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Pavel [41]
3 years ago
8

3(2z−4)=−6(2−z). help plss

Mathematics
1 answer:
stellarik [79]3 years ago
5 0

Answer: (6z-12) = (-12+6z)

Step-by-step explanation:

Okay, so what you want to do is multiply 3(2z-4) and you should get (6z-12). Then you do the exact same thing on the other side, -6(2-z), and you should get (-12+6z). Then you put those together, so it would look like (6z-12) = (-12+6z).

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Answer:

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Step-by-step explanation:

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What number must you add to complete the square? x^2+14x=-7
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4 years ago
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Find the inverse of the function
lozanna [386]

as you already know, to get the inverse of any expression we start off by doing a quick switcheroo on the variables and then solving for "y", let's do so.

\stackrel{h(x)}{y}~~ = ~~6\sqrt[3]{2x+5}-1\implies \stackrel{\textit{quick switcheroo}}{x~~ = ~~6\sqrt[3]{2y+5}-1} \\\\\\ x+1=6\sqrt[3]{2y+5}\implies \cfrac{x+1}{6}=\sqrt[3]{2y+5}\implies \left( \cfrac{x+1}{6} \right)^3=\left( \sqrt[3]{2y+5} \right)^3

\left( \cfrac{x+1}{6} \right)^3=2y+5\implies \left( \cfrac{x+1}{6} \right)^3-5=2y\implies \cfrac{\left( \frac{x+1}{6} \right)^3-5}{2}=y \\\\\\ \cfrac{\left( \frac{x+1}{6} \right)^3}{2}-\cfrac{5}{2}=y\implies \cfrac{~~ \frac{(x+1)^3}{6^3}~~}{2}-\cfrac{5}{2}=y\implies \cfrac{(x+1)^3}{432}-\cfrac{5}{2}=\stackrel{y}{h^{-1}(x)}

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