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3 years ago

Help me on these questions plz

Mathematics

1 answer:

Misha Larkins [42]3 years ago

8 0

1)

x/3 - 4 = 5
x/3 = 9
x = 27

2)

x/4 = 3/8
8x = 12
x = 1.5 or 3/2

3)

4x = 3/8
4x = 0.375
x = 0.09375 or 3/32

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Assume that thermometer readings are normally distributed with a mean of degrees and a standard deviation of 1.00degrees C. A th

Andrew [12]

Answer:

0.2684 is the probability that the temperature reading is between 0.50 and 1.75.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0 degrees

Standard Deviation, σ = 1 degrees

We are given that the distribution of thermometer readings is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(Between 0.50 degrees and 1.75 degrees)

$P(0.50 \leq x \leq 1.75)\\\\ = P(\displaystyle\frac{0.50 - 0}{1} \leq z \leq \displaystyle\frac{1.75-0}{1})\\\\ = P(0.50 \leq z \leq 1.75)\\= P(z \leq 1.75) - P(z < 0.50)\\= 0.9599 - 0.6915 = 0.2684 = 26.84\%$

0.2684 is the probability that the temperature reading is between 0.50 and 1.75.

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3 years ago

A mixed economy is dependent only on the choices of individuals and businesses a combination of individual choice and government

bekas [8.4K]

Answer:

In general, a mixed economy is "a combination of individual choice and government protection," although the balance tends to lean more towards individual choice.

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2 years ago

Read 2 more answers

Help please. (Simple question)

vladimir1956 [14]

Both missing angles are 45°

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2 years ago

Anyone know how to solve this?

yuradex [85]

Answer:

Step-by-step explanation:

<h3> $( - \frac{4}{5})^{2}$ </h3><h3> ${( - 1)}^{2} \frac{ {4}^{2} }{ {5}^{2} }$ </h3><h3> $1 \frac{ {4}^{2} }{ {5}^{2} }$ </h3><h3> $\frac{ {4}^{2} }{ {5}^{2} }$ </h3><h3> $\frac{16}{25}$ </h3><h3>Hope it is helpful....</h3>

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

$\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}$

and it follows that

$\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}$

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1 year ago