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KatRina [158]
3 years ago
10

If you place a 13 foot ladder against the top of a 12 foot building, how many feet will the bottom of the ladder be from the bot

tom of the building?
Mathematics
1 answer:
zvonat [6]3 years ago
7 0
Did this a while ago but I’m pretty sure it’s 5 feet x=5
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Helpppp
earnstyle [38]

Answer:

Y=2x-5

Step-by-step explanation:

please mark me as brainlest

7 0
3 years ago
Find the surface area of the part of the circular paraboloid z=x^2+y^2 that lies inside the cylinder X^2+y^2=1
hichkok12 [17]

Answer:

\mathbf{\dfrac{\pi}{6}[5 \sqrt{5}-1]}

Step-by-step explanation:

Given that:

The surface area (S.A) z = x^2 +y^2

Hence the S.A is of form z = f(x,y)

Then the S.A can be represented with the equation

A(S) = \iint _D \sqrt{1+ (\dfrac{\partial z}{\partial x})^2+ (\dfrac{\partial z}{\partial y})^2} \ dA

where :

D = cylinder x^2 +y^2 =1

In polar co-ordinates:

D = {(r, θ): 0≤ r ≤ 1, 0 ≤ θ ≤ 2π)

Similarly, \dfrac{\partial z}{\partial x} = 2x and \dfrac{\partial z}{\partial y} = 2y

Therefore;

S.A = \iint_D \sqrt{1+4x^2+4y^2} \ dA

= \iint_D \sqrt{1+4(x^2+y^2)} \ dA

= \int^{2 \pi}_{0} \int^{1}_{0}  \sqrt{1+4r^2} \ r \ dr \d \theta

= [\theta]^{2 \pi}_{0} \dfrac{1}{8}\times \dfrac{2}{3}\begin {bmatrix} (1+4r^2)^{\dfrac{3}{2}}\end {bmatrix}^1_0

= 2 \pi \times \dfrac{1}{12}[5^{\dfrac{3}{2}} - 1]

\mathbf{=\dfrac{\pi}{6}[5 \sqrt{5}-1]}

6 0
3 years ago
Choose the correct written expression for: 25 – (3 x 4).
just olya [345]

Answer:

the quotient of 3 and 4 subtracted from 25.

Step-by-step explanation:

3 0
2 years ago
Will upvoate all
nalin [4]
I think the answer is going to be a
7 0
3 years ago
I need help with this geometry math assignment I been struggling and I need help on it very fast and it is due today so please h
deff fn [24]

Answer:

One tip: Do the top first

Step-by-step explanation:

4 0
3 years ago
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