Hence, the sum of the given GP is 16347
<h2>What is a series?</h2>
a series is the cumulative sum of a given sequence of terms. Typically, these terms are real or complex numbers, but much more generality is possible.
<h3>How to solve?</h3>
we can identify from the given geomertric series.
first term = a(say) = 3
geometric factor of progression = r(say) = 4
Sum of the first 7 terms = a(
) ,where n is 7
Sum = 3(
) = 16348-1
= 16347
Hence, the sum of the given GP is 16347.
to learn more about series: brainly.com/question/12578626
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19.8 rounded to 1 s.f. is
20
Well, first, the equation that you are looking for is Y = MX + B. To find B, look at the first dot on the Y-axis. It starts at positive 3, so, you know your equation will end with +3. Next, to find MX, start at the either dot, and find the Rise/Run. In this particular equation, the rise is 1, and, the run is -2, because it's going backwards (negative line). Meaning, the line's equation would be, f( x )= -1/2x + 3.
To find W⊥, you can use the Gram-Schmidt process using the usual inner-product and the given 5 independent set of vectors.
<span>Define projection of v on u as </span>
<span>p(u,v)=u*(u.v)/(u.u) </span>
<span>we need to proceed and determine u1...u5 as: </span>
<span>u1=w1 </span>
<span>u2=w2-p(u1,w2) </span>
<span>u3=w3-p(u1,w3)-p(u2,w3) </span>
<span>u4=w4-p(u1,w4)-p(u2,w4)-p(u3,w4) </span>
<span>u5=w5-p(u4,w5)-p(u2,w5)-p(u3,w5)-p(u4,w5) </span>
<span>so that u1...u5 will be the new basis of an orthogonal set of inner space. </span>
<span>However, the given set of vectors is not independent, since </span>
<span>w1+w2=w3, </span>
<span>therefore an orthogonal basis cannot be found. </span>
Answer:
The coordinates of point Q' would be (5, -6) after being translated 1 unit to the right.
Step-by-step explanation:
